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3 years ago

25 points and brainiest badge

Mathematics

2 answers:

VikaD [51]3 years ago

5 0

Answer:

Step by step explanation

Diano4ka-milaya [45]3 years ago

3 0

Answer:

150°

Step-by-step explanation:

The 70° angle is on a straight line so to find the next angel for the triangle

180-70=110

Angles in a triangle adds up to 180

110+40=150

180-150=30

Therefore the angle near x in the triangle is 30

To find x

180-30=150°

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What are the intercepts? type an ordered pair.

Sunny_sXe [5.5K]

Answer: the x-intercepts are -4 and 2. The y-intercept(s) is 2

Step-by-step explanation:

8 0

4 years ago

Read 2 more answers

The cost of six hens and one duck at the university poultry farm is GH₵40. While four hens and three ducks cost GH₵36. What is t

Anon25 [30]

Answer:

Step-by-step explanation:

Let's call hens h and ducks d. The first algebraic equation says that 6 hens (6h) plus (+) 1 duck (1d) cost (=) 40.

The second algebraic equations says that 4 hens (4h) plus (+) 3 ducks (3d) cost (=) 36.

The system is

6h + 1d = 40

4h + 3d = 36

The best way to go about this is to solve it by substitution since we have a 1d in the first equation. We will solve that equation for d since that makes the most sense algebraically. Doing that,

1d = 40 - 6h.

Now that we know what d equals, we can sub it into the second equation where we see a d. In order,

4h + 3d = 36 becomes

4h + 3(40 - 6h) = 36 and then simplify. By substituting into the second equation we eliminated one of the variables. You can only have 1 unknown in a single equation, and now we do!

4h + 120 - 18h = 36 and

-14h = -84 so

h = 6.

That means that each hen costs $6. Since the cost of a duck is found in the bold print equation above, we will sub in a 6 for h to solve for d:

1d = 40 - 6(6) and

d = 40 - 36 so

d = 4.

That means that each duck costs $4.

3 0

4 years ago

Five cards are drawn from a standard 52-card playing deck. A gambler has been dealt five cards—two aces, one king, one 3, and on

Nookie1986 [14]

Answer:

The probability that he ends up with a full house is 0.0083.

Step-by-step explanation:

We are given that a gambler has been dealt five cards—two aces, one king, one 3, and one 6. He discards the 3 and the 6 and is dealt two more cards.

We have to find the probability that he ends up with a full house (3 cards of one kind, 2 cards of another kind).

We know that gambler will end up with a full house in two different ways (knowing that he has given two more cards);

If he is given with two kings.
If he is given one king and one ace.

Only in these two situations, he will end up with a full house.

Now, there are three kings and two aces left which means at the time of drawing cards from the deck, the available cards will be 47.

So, the ways in which we can draw two kings from available three kings is given by = $\frac{^{3}C_2 }{^{47}C_2}$ {∵ one king is already there}

= $\frac{3!}{2! \times 1!}\times \frac{2! \times 45!}{47!}$ {∵ $^{n}C_r = \frac{n!}{r! \times (n-r)!}$ }

= $\frac{3}{1081}$ = 0.0028

Similarly, the ways in which one king and one ace can be drawn from available 3 kings and 2 aces is given by = $\frac{^{3}C_1 \times ^{2}C_1 }{^{47}C_2}$

= $\frac{3!}{1! \times 2!}\times \frac{2!}{1! \times 1!} \times \frac{2! \times 45!}{47!}$

= $\frac{6}{1081}$ = 0.0055

Now, probability that he ends up with a full house = $\frac{3}{1081} + \frac{6}{1081}$

= $\frac{9}{1081}$ = 0.0083.

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4 years ago

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Which statement is false?(1 point)

Sergio039 [100]

A.Fractions and decimals are not integers. All whole numbers areintegers (and all natural numbers are integers), but not all integersare whole numbers or natural numbers. For example, -5 is an integerbut not a whole number or a natural number.
B.A number is rational if it can be represented as p q with p , q ∈ Z and q ≠ 0 . Any number which doesn't fulfill the above conditions is irrational. It can be represented as a ratio of two integers as well as ratio of itself and an irrational number such that zero is not dividend in any case
C.In mathematics, an irrational number is any real number that cannot be expressed as a ratio of integers. Irrational numbers cannot be represented as terminating or repeating decimals.
D.The correct answer is rational and real numbers, because all rational numbers are also real. Correct. The number is between integers, so it can't be an integer or a whole number. It's written as a ratio of two integers, so it's a rational number and not irrational.
 Witch one do u think it is??

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3 years ago

Which expression can be modeled using the number line?

uranmaximum [27]

Answer:

iohji

Step-by-step explanation:

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3 years ago