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lys-0071 [83]
3 years ago
15

The set S consists of all odd multiples of 3: S = {..., -9, -3, 3, 9,...}. If the integers x and y are in S, then which of the f

ollowing must also be in S?
A) xy
B) x + y
C) x - y
D) x/y
E) -x - y

Explain too, thanks.
Mathematics
1 answer:
tankabanditka [31]3 years ago
4 0
I think it is gonna be xy

because if ur set contains all odd multiples of 3 (-9,-3,3,9,15,21,27...
and u pick any 2 of those numbers and multiply them u will end up with an odd numbered multiple of 3

and if u pick out any 2 numbers in ur set..and do any of the other things in ur answer choices, it will not always be an odd numbered multiple of 3
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What is -1/p^-6 ???​
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3 years ago
Use the point-slope formula to write an equation of the line that passes through (4,10) and has a slope of m= 3. Write the
baherus [9]
Answer:
3x --y -2= 0
Step-by-step explanation:
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2 years ago
Plastic parts produced by an injection-molding operation are checked for conformance to specifications. Each tool contains 15 ca
Rainbow [258]

Answer:

(A) 0.006593 or 0.6593%

(B) 0.01538 or 1.538%

Step-by-step explanation:

The total number of possibilities to pick 3 parts out of 15 possible parts is given by the following combination:

n=\frac{15!}{(15-3)!3!}=\frac{15*14*13}{3*2*1}\\n=455\ ways\\

(A) There are only three possibilities for which the inspector finds exactly one nonconforming part (NCC, CNC, CCN). Therefore, the probability is:

P(N=1) = \frac{3}{455}=0.006593 =0.6593\%

(B) There are three possibilities  for which the inspector finds exactly one nonconforming part, three possibilities for two nonconforming parts (NNC, CNN, NCN), and one possibility for all nonconforming parts (NNN). The probability that the inspector finds at least one nonconforming part is:

P(N>0) =P(N=1)+P(N=2)+P(N=3) \\P(N>0) = \frac{3}{455}+ \frac{3}{455}+ \frac{1}{455}\\P(N>0) =0.01538 =1.538\%

5 0
3 years ago
Question 8 Multiple Choice Worth 1 points)
bogdanovich [222]

Answer:

Option B.

Step-by-step explanation:

Note: The function f(x) is not in correct format it must be f(x)=3^x.

It is given that two different plants that grow each month at different rates are represented by the functions f(x) and g(x).

Let as consider the two functions,

f(x)=3^x

g(x)=5x+12

Now, table of values is

Month(x)        f(x)=3^x           g(x)=5x+12

    1                      3                          17

    2                     9                         22

    3                     27                        27

    4                     81                        32

From the above table it is clear that in first and second month the height of the f(x) plant is less than of g(x).

In month 3, heights are equal.

In month 4, height of the f(x) plant exceed that of the g(x) plant.

Therefore, the correct option is B.

4 0
3 years ago
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