1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Rashid [163]
3 years ago
8

Please Help me I’m begging you

Mathematics
1 answer:
eduard3 years ago
4 0

Answer:

A

Step-by-step explanation:

You might be interested in
How many 3/4 cup servings are in 1/2 of a cup of milk? Write your answer in simplest form.
Gekata [30.6K]
The answer to this question would be: 0.375 cups of milk

In this question, you are asked how many cups of milk is 3/4 serving from 1/2 cup of milk. To answer this, you need to multiply the number of serving with the serving size.<span>
</span>If one serving is 1/2 cups of milk, then 3/4 servings would be:
3/4 servings * (0.5 cups / serving)= 3/8 cups of milk = 0.375 cups of milk
5 0
2 years ago
Read 2 more answers
GIVING BRAINLIEST! The triangles below are similar. How tall is the tree? Please show process.
EleoNora [17]

Answer:

Height of tree= 20

Please give me brainliest if you can

Step-by-step explanation:

x= height of tree

2/3= x/30

3x= 2(30)

3x= 60

/3    /3

x= 20

7 0
3 years ago
Read 2 more answers
Every day for 5 days Jack and Jill went walking. Each day Jack walked 4/5 of a mile and Jill walked 2/3 of a mile. At the end of
DanielleElmas [232]

\bf \stackrel{\textit{Jack for 7 days}}{7\left( \cfrac{4}{5} \right)}\implies \cfrac{28}{5}~\hspace{10em}\stackrel{\textit{Jill for 7 days}}{7\left( \cfrac{2}{3} \right)}\implies \cfrac{14}{3}&#10;\\\\[-0.35em]&#10;~\dotfill\\\\&#10;\cfrac{28}{5}-\cfrac{14}{3}\implies \stackrel{\textit{LCD of 15}}{\cfrac{(3)28-(5)14}{15}}\implies \cfrac{84-70}{15}\implies \cfrac{14}{15}

7 0
2 years ago
Simplify the following: <br> 8h – 4g + 5g + 2h
Talja [164]

8h - 4g + 5g + 2h \\  \\ (8h + 2h) -(4g - 5g) \\  \\ 10h - ( - g) \\  \\ 10h + g
5 0
3 years ago
The CPA Practice Advisor reports that the mean preparation fee for 2017 federal income tax returns was $273. Use this price as t
skad [1K]

Answer:

a) 0.6212 = 62.12% probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean.

b) 0.7416 = 74.16% probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean.

c) 0.8804 = 88.04% probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean.

d) None of them ensure, that one which comes closer is a sample size of 100 in option c), to guarantee, we need to keep increasing the sample size.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

The CPA Practice Advisor reports that the mean preparation fee for 2017 federal income tax returns was $273. Use this price as the population mean and assume the population standard deviation of preparation fees is $100.

This means that \mu = 273, \sigma = 100

A) What is the probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean?

Sample of 30 means that n = 30, s = \frac{100}{\sqrt{30}}

The probability is the p-value of Z when X = 273 + 16 = 289 subtracted by the p-value of Z when X = 273 - 16 = 257. So

X = 289

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{289 - 273}{\frac{100}{\sqrt{30}}}

Z = 0.88

Z = 0.88 has a p-value of 0.8106

X = 257

Z = \frac{X - \mu}{s}

Z = \frac{257 - 273}{\frac{100}{\sqrt{30}}}

Z = -0.88

Z = -0.88 has a p-value of 0.1894

0.8106 - 0.1894 = 0.6212

0.6212 = 62.12% probability that the mean price for a sample of 30 federal income tax returns is within $16 of the population mean.

B) What is the probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean?

Sample of 30 means that n = 50, s = \frac{100}{\sqrt{50}}

X = 289

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{289 - 273}{\frac{100}{\sqrt{50}}}

Z = 1.13

Z = 1.13 has a p-value of 0.8708

X = 257

Z = \frac{X - \mu}{s}

Z = \frac{257 - 273}{\frac{100}{\sqrt{50}}}

Z = -1.13

Z = -1.13 has a p-value of 0.1292

0.8708 - 0.1292 = 0.7416

0.7416 = 74.16% probability that the mean price for a sample of 50 federal income tax returns is within $16 of the population mean.

C) What is the probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean?

Sample of 30 means that n = 100, s = \frac{100}{\sqrt{100}}

X = 289

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{289 - 273}{\frac{100}{\sqrt{100}}}

Z = 1.6

Z = 1.6 has a p-value of 0.9452

X = 257

Z = \frac{X - \mu}{s}

Z = \frac{257 - 273}{\frac{100}{\sqrt{100}}}

Z = -1.6

Z = -1.6 has a p-value of 0.0648

0.9452 - 0.0648 =

0.8804 = 88.04% probability that the mean price for a sample of 100 federal income tax returns is within $16 of the population mean.

D) Which, if any of the sample sizes in part (a), (b), and (c) would you recommend to ensure at least a .95 probability that the same mean is withing $16 of the population mean?

None of them ensure, that one which comes closer is a sample size of 100 in option c), to guarantee, we need to keep increasing the sample size.

6 0
2 years ago
Other questions:
  • Which statement about histograms is true?
    14·2 answers
  • there are 36 cans of beans and 48 cans of corn. the display designer wants an equal number of each vegetables in each row. what
    14·1 answer
  • The revenue, in dollars, of a company that produces jeans can be modeled by 2x2 + 17x – 175. The cost, in dollars, of producing
    11·1 answer
  • How do you expand <img src="https://tex.z-dn.net/?f=%28x-1%29%5E%7B4%7D%20%20" id="TexFormula1" title="(x-1)^{4} " alt="(x-1)^{
    10·1 answer
  • What’s number 2 4 and 5
    6·1 answer
  • A geometric figure is in the yellow region what is not true about one of its properties
    7·1 answer
  • Which graph shows four points that represent equivalent ratios? (The first linked pic is A and B, the second linked pic is C and
    9·1 answer
  • Select the correct answer.
    6·2 answers
  • A regular polygon has
    14·2 answers
  • Charnise uses 3 gal. red paint to 5 gal. white paint to make pink paint. She
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!