Answer:
w=17
Step-by-step explanation:
-243=-9(10+w)
-243=-90-9w
+90 +90
-153=-9w
17=w
hope this helps :)
This is the formula of finding the hypotenuse: a² + b² = c².
So the legs would be a and b.
4² + 4² = c²
c² = 16 + 16
c² = 32
c = √32 (Option C)
Answer:
t≈8.0927
Step-by-step explanation:
h(t) = -16t^2 + 128t +12
We want to find when h(t) is zero ( or when it hits the ground)
0 = -16t^2 + 128t +12
Completing the square
Subtract 12 from each side
-12 = -16t^2 + 128t
Divide each side by -16
-12/-16 = -16/-16t^2 + 128/-16t
3/4 = t^2 -8t
Take the coefficient of t and divide it by 8
-8/2 = -4
Then square it
(-4) ^2 = 16
Add 16 to each side
16+3/4 = t^2 -8t+16
64/4 + 3/4= (t-4)^2
67/4 = (t-4)^2
Take the square root of each side
±sqrt(67/4) =sqrt( (t-4)^2)
±1/2sqrt(67) = (t-4)
Add 4 to each side
4 ±1/2sqrt(67) = t
The approximate values for t are
t≈-0.092676
t≈8.0927
The first is before the rocket is launched so the only valid answer is the second one
Answer:
y=2x+5 is the answer ALSO CAN WE TALK ABOUT THE FACT THAT MOO975 IS ON THREE QUESTIONS AT THE SAME TIME
Step-by-step explanation:
