Answer:
It is the distance that - 5 is from 0 on the number line.
Step-by-step explanation:
We have to select a statement that is true about the value of StartAbsoluteValue negative 5 EndAbsoluteValue i.e. |- 5|
Definition of the absolute value function is given by, |x| = x for, x ≥ 0 and |x| = - x for x < 0.
Now, an absolute value function gives the positive value of any value in the function i.e. |- 5| = 5.
Therefore, it is the distance that - 5 is from 0 on the number line. (Answer)
9514 1404 393
Answer:
DE = 86
EF = 84
Step-by-step explanation:
We assume that point E lies on segment DF, so that ...
DE + EF = DF
(3x +20) +(2x +40) = 170
5x = 110 . . . . . . . . . . . . . . . collect terms, subtract 60
x = 22 . . . . . . . . . . . . divide by 5
DE = 3×22 +20 = 66 +20 = 86
EF = 2×22 +40 = 44 +40 = 84
