Answer:
The difference quotient for is
.
Step-by-step explanation:
The difference quotient is a formula that computes the slope of the secant line through two points on the graph of <em>f</em>. These are the points with x-coordinates x and x + h. The difference quotient is used in the definition the derivative and it is given by
So, for the function the difference quotient is:
To find , plug
instead of
Finally,
The difference quotient for is
.
Answer:
C
Step-by-step explanation:
Calculate AC using Pythagoras' identity in ΔABC
AC² = 20² - 12² = 400 - 144 = 256, hence
AC = = 16
Now find AD² from ΔACD and ΔABD
ΔACD → AD² = 16² - (20 - x)² = 256 - 400 + 40x - x²
ΔABD → AD² = 12² - x² = 144 - x²
Equate both equations for AD², hence
256 - 400 + 40x - x² = 144 - x²
-144 + 40x - x² = 144 - x² ( add x² to both sides )
- 144 + 40x = 144 ( add 144 to both sides )
40x = 288 ( divide both sides by 40 )
x = 7.2 → C
Answer:
Option A) (2.5,-1.3) is correct
The midpoint of the given line segment is M=(2.5,-1.3)
Step-by-step explanation:
Given that the line segment with end points (3.5, 2.2) and (1.5, -4.8)
To find the mid point of these endpoints midpoint formula is
Let () be the point (3.5, 2.2) and (
) be the point (1.5, -4.8)
substituting the points in the formula
Therefore M=(2.5,-1.3)
The midpoint of the given line segment is M=(2.5,-1.3)