Answer:
Distance between school and home = 105 miles.
Step-by-step explanation:
Let distance = D miles
Time to take walking/jogging, t1 = D/6 hours
Time by car, t2 = D/35 hours
Average time, t
= (t1+t2)/2
= D(1/6+1/35)
= (D/210)(35+6)
=41D/210 hours
Given t = t1-3 hours
41D/210 - D/6 = 3
Solve for D
41D/210 - 35D/210 = 3
(41-35)D/210 = 3
6D/210 = 3
D = 3*210/6 = 105 miles.
(Appreciate very much Diana's efforts to walk/job 105 miles to school, and we understand how lucky we are in most of Europe and North America)
Answer:
B. 3.
Step-by-step explanation:
At the limit we can take the numerator to be √(9x^4) = 3x^2
The function is of the form ∞/ ∞ as x approaches ∞ so we can apply l'hopitals rule:
Differentiating top and bottom we have 6x / 2x - 3. Differentiating again we get 6 / 2 = 3.
Our limit as x approaches infinity is 3.
200/5 = 40 mph 200/4 = 50 mph Let x be the speed in still waters and y the speed of current. x + y = 50 x - y = 40 ADD 2x = 90 x = 45 mph ANSWER is C) 2) C
You can take LCM and then can add to see what's the sum.
The sum result of given expressions is given by: 
<h2>Given that:</h2>
- To find sum of
and 
<h2>Finding LCM and summing:</h2>
You can take LCM and then can add to see whats the sum.
Thus, the sum of given expressions is given by:
Learn more about algebraic sums here:
brainly.com/question/14964662
