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-BARSIC- [3]
4 years ago
7

Solve for x in the given interval. sec x= -2√3/3, for π/2 ≤x≤π

Mathematics
1 answer:
drek231 [11]4 years ago
4 0

Answer:

b. x=\frac{5\pi}{6}

Step-by-step explanation:

The given function is

\sec x=-\frac{2\sqrt{3} }{3},\:\:for\:\:\frac{\pi}{2}\le x \le \pi

Recall that the reciprocal of the cosine ratio is the secant ratio.

This implies that;

\frac{1}{\cos x}=-\frac{2\sqrt{3} }{3}

\Rightarrow \cos x=-\frac{3}{2\sqrt{3} }

\Rightarrow \cos x=-\frac{\sqrt{3}}{2}

We take the inverse cosine of both sides to obtain;

x=\cos^{-1}(-\frac{\sqrt{3}}{2})

x=\frac{5\pi}{6}

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