Help me pls dont write fake answers pls

1 answer:

6 0

Answer:

it’s C, 5.2

hope i helped

ur wlcm :)

correct me if im wrong

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ValentinkaMS [17]

$square = 3 \times 3 = 9 \\ rectangle = 2 \times (4 + 3) = 14 \\ the \: whole \: shape = 14 + 9 = 23$

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Sindrei [870]

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-BARSIC- [3]

Answer:

$\displaystyle x=-1, \ 8$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Algebra I

Step-by-step explanation:

Step 1: Define

Identify variables

x² - 7x - 8

↓

a = 1, b = -7, c = -8

Step 2: Solve for x

Substitute in variables [Quadratic Formula]: $\displaystyle x=\frac{7 \pm \sqrt{(-7)^2-4(1)(-8)}}{2(1)}$
[√Radical] Evaluate exponents: $\displaystyle x=\frac{7 \pm \sqrt{49-4(1)(-8)}}{2(1)}$
[√Radical] Multiply: $\displaystyle x=\frac{7 \pm \sqrt{49 + 32}}{2(1)}$
[√Radical] Add: $\displaystyle x=\frac{7 \pm \sqrt{81}}{2(1)}$
[√Radical] Evaluate: $\displaystyle x=\frac{7 \pm 9}{2(1)}$
Multiply: $\displaystyle x=\frac{7 \pm 9}{2}$
Add/Subtract: $\displaystyle x=\frac{-2}{2}, \ \frac{16}{2}$
Divide: $\displaystyle x=-1, \ 8$