union=( -2,-1,0,1,2,5,7,8) intersection= -1,1
The numbers given in the problem above are part of an arithmetic sequence with first and sixth terms equal to -21 and -36, respectively. Firstly, calculate for the common difference (d).
d = (-36 - -21) / (6 - 1) = -3
The arithmetic mean is calculated by adding -3 to the term prior to it.
a2 = -21 + -3 = -24 a3 = -24 + -3 = -27
a4 = -27 + -3 = -30 a5 = -30 + -3 = -33
Thus the four arithmetic means are -24, -27, -30, and -33.
It is not too difficult. Just do this
50-15
5(10-3)
The answer is 5(10-3)
I am pretty sure it is customary
Use the property of distribution:
a(b+c) = ab + ac
4(4a+5) = 4(4a) + 4(5)
4(4a+5) = 16a + 20
Hope that helps :)
