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Ugo [173]
3 years ago
5

The life of light bulbs is distributed normally. The standard deviation of the lifetime is 20 hours and the mean lifetime of a b

ulb is 500 hours. Find the probability of a bulb lasting for between 480 and 526 hours.
Mathematics
1 answer:
FinnZ [79.3K]3 years ago
5 0

Answer:

The probability of a bulb lasting for between 480 and 526 hours=0.74454

Step-by-step explanation:

We are given that

Standard deviation of the lifetime,\sigma=20hours

Mean, \mu=500hours

We have to find the probability of a bulb lasting for between 480 and 526 hours.

P(480

P(480

P(480

P(480

P(480

Hence, the probability of a bulb lasting for between 480 and 526 hours=0.74454

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The perimeter of the new m-phone is 16 inches. The phones length is 5.25 inches. What is the width of the phone
True [87]
Perimeter is all the sides added up together.
Divide 16 by 2, so that you can get just a measurement of the length and the width.

16/2 = 8

Since the length is 5.25, subtract that by 8.

8-5.25 = 2.75

The width of the phone is 2.75 inches.
5 0
3 years ago
I need to know how to do this math problem
ladessa [460]

figure it out yourself

5 0
3 years ago
Worth 20 points
bezimeni [28]

Answer:

1. 1/8 ÷ 3/4 = 1/6

2. 3/5 ÷ 3/2 = 2/5

3. 4/1 ÷ 2/3 = 6

4.9/4 ÷ 6/5 = 15/8

5.22/4 ÷ 2/5 = 261/80

Step-by-step explanation:

Hope this Helped

5 0
3 years ago
Please help!!!
xxMikexx [17]

Answer:

A = 1.5 π in² ≈ 4.7 in²

Step-by-step explanation:

the area (A) of the sector is calculated as

A = area of circle × fraction of circle

   = πr² × \frac{\frac{\pi }{3} }{2\pi }

  = π × 3² × \frac{1}{6}

  = 9π × \frac{1}{6}

  =  1.5π in²

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7 0
2 years ago
Determine whether The given segments have the same length. Justify your answer
Semenov [28]

We know the distance formula is

\sqrt{ (x_{2}-x_{1})^2+ (y_{2}-y_{1})^2 }

9)

Here A( -4,2) and B(1,4)

So length of AB

= \sqrt{(1-(-4))^2+(4-2)^2} =\sqrt{5^2+2^2} =\sqrt{29}

Also C(2,1)

Length of BC

= \sqrt{(2-1)^2+(-1-4)^2} =\sqrt{1^2+(-5)^2} =\sqrt{26}

So we can see that length of AB is not equal to length of BC

11.

Now AB = \sqrt{29}

Also C(2,-1) & D(4,4)

Length of CD

= \sqrt{(4-2)^2+(4-(-1)) ^2} =\sqrt{2^2+5^2} =\sqrt{29}

Yes AB = CD

5 0
3 years ago
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