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3 years ago

Solve x-3/6 divided by 3-x/2 Please show work

Mathematics

1 answer:

Nataly_w [17]3 years ago

4 0

$\cfrac{x-3}{6}: \cfrac{3-x}{2} = -\cfrac{3-x}{6}*\cfrac{2}{3-x} =- \cfrac{2}{6}=- \cfrac{1}{3}$

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Gerry is knitting a scarf for a friend. She knits a gauge swatch which measures 4 in. by 4 in. If the square is 30 stitches wide

LiRa [457]

Answer:

Gerry will need to knit 135 stitches wide and 351 rows long for make a scarf that is 18 inches wide and 36 inches long.

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Measures of the gauge swatch = 4 inches * 4 inches

Number of stitches wide of the gauge swatch = 30

Number of rows long of the gauge swatch = 39

2. How many stitches wide will she need to knit in order to make a scarf that is 18 inches wide and 36 inches long?

Using Rule of Three Simple we can found that value, this way;

Number of stitches wide for 18 inches wide = (18 * 30)/4

Number of stitches wide for 18 inches wide = 540/4 = 135

Gerry will need to knit 135 stitches wide for make a scarf that is 18 inches wide.

We can found the same way, the rows long:

Number of rows long for 36 inches long = (36 * 39)/4

Number of rows long for 36 inches long = 1,404/4 = 351

Gerry will need to knit 351 rows long for make a scarf that is 36 inches long.

8 0

3 years ago

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KatRina [158]

Answer:

37.5%

Step-by-step explanation:

I don't have a step-by-step explanation, and I don't know if this is right. It doesn't give me enough time to solve it. If an expert could check this, it would be highly appreciated!

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3 years ago

Quadratic equation whose roots are 6 and 4, and whose leading coefficient is 5 .

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Answer:

f(x)= 5x^(2)-10x-120

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3 years ago

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3 years ago

The miles-per-gallon rating of passenger cars is a normally distributed random variable with a mean of 33.8 mpg and a standard d

EleoNora [17]

Answer:

The probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

Step-by-step explanation:

Let the random variable X represent the miles-per-gallon rating of passenger cars.

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Compute the probability that a randomly selected passenger car gets more than 37.3 mpg as follows:

$P(X>37.3)=P(\frac{X-\mu}{\sigma}>\frac{37.3-33.8}{3.5})$

$=P(Z>1)\\\\=1-P(Z$

Thus, the probability that a randomly selected passenger car gets more than 37.3 mpg is 0.1587.

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3 years ago