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Naddika [18.5K]
3 years ago
14

Solve x-3/6 divided by 3-x/2 Please show work

Mathematics
1 answer:
Nataly_w [17]3 years ago
4 0
\cfrac{x-3}{6}: \cfrac{3-x}{2}  = -\cfrac{3-x}{6}*\cfrac{2}{3-x}  =- \cfrac{2}{6}=- \cfrac{1}{3}
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B Which of the statements is true about the polygons below E D 120 degrees C 90 90 60 60 120 degrees 90 90 F D Polygon A Polygon
Serhud [2]

The statement that is true about the polygons is: the opposite angles of the rectangle are supplementary, therefore, a circle can be circumscribed about the rectangle.

<h3>What is a Circumscribed Quadrilateral?</h3>

An circumscribed quadrilateral is a quadrilateral whose four side lie tangent to the circumference of a circle. The opposite angles in an inscribed quadrilateral are supplementary, that is, when added together, their sum equals 180 degrees.

From the two figures given, the opposite angles of the rectangle are supplementary, therefore, a circle can be circumscribed about the rectangle. (Option D).

Learn more about circumscribed quadrilateral on:

brainly.com/question/26690979

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7 0
2 years ago
Can someone help me with this please!!
Elenna [48]

Step-by-step explanation:

part A

all listed features (A - F) are correct and to be selected.

part B

the average rate of change is

(f(x2) - f(x1)) / (x2 - x1)

so,

(f(0) - f(-2)) / (0 - -2) = (2 - 0) / (0 + 2) = 2/2 = 1

8 0
2 years ago
|v+8| -5=2 Help please
Galina-37 [17]

Answer:

v= -1 (BRAINLIEST PLEASE)

Step-by-step explanation:

|v+8| -5=2

Add 5 to each side

|v+8| -5=2

      +5= +5

Now you have |v+8|= 7

So what plus 8 equals 7?

-1

so now you have |-1+8| which is 7

so v= -1

3 0
4 years ago
What is the property of 2*1=2
MakcuM [25]
That is called the multiplicative identity property.
5 0
3 years ago
Triangle J K L is shown. Angle J K L is 120 degrees and angle K L J is 40 degrees. The length of K L is 2 and the length of J L
Veseljchak [2.6K]

Answer:

k \approx 5$ units

Step-by-step explanation:

In Triangle JKL

\angle K=120^\circ\\\angle L=40^\circ\\KL=2\\JL=k

We want to determine the approximate value of k using the law of sines.

\angle J+\angle K+\angle L=180^\circ $ (Sum of angles in a \triangle)\\\angle J+120^\circ+40^\circ=180^\circ \\\angle J=180^\circ-(120^\circ+40^\circ)=20^\circ

Using Law of Sines

\dfrac{k}{\sin K} =\dfrac{j}{\sin J} \\\dfrac{k}{\sin 120} =\dfrac{2}{\sin 20} \\k=\sin 120 \times \dfrac{2}{\sin 20}\\k=5.06\\k \approx 5$ units

7 0
3 years ago
Read 2 more answers
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