Answer:
Tired
Step-by-step explanation:
Considering the perimeter of the rectangle, we have that the length is of 9 inches and the width is of 55 inches.
<h3>What is the perimeter of a rectangle?</h3>
The perimeter of a rectangle of length l and width w is given as follows:
P = 2(l + w).
The length is an odd integer and the width is <u>5 times the next consecutive odd integer,</u> hence:
l = x, w = 5(x + 2).
The perimeter is of 128 inches, hence:
128 = 2l + 2w
128 = 2x + 10(x + 2)
128 = 2x + 10x + 20
12x = 108
x = 9.
Hence the length is of 9 inches and the width is of 55 inches.
More can be learned about the perimeter of a rectangle at brainly.com/question/10489198
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Answer:
We can conclude that on this case we have identical processes but excersise 17 use another way to present the probability distribution and as we can see the expected value can be viewed as a dot product of two vectors with one vector containing the outcomes and the other the probabilities for each possible outcome.
Step-by-step explanation:
Assuming this previous info:
Exercise 17. Suppose that we convert the table on the previous page displaying the discrete distribution for the number of heads occurring when two coins are flipped to two vectors.
Let vector
Answer:
72 ft
Step-by-step explanation:
Here, we want to get the maximum height the ball will reach
the maximum height the ball will reach is equal to the y-coordinate of the vertex of the equation
So we need firstly, the vertex of the given quadratic equation
The vertex can be obtained by the use of plot of the graph
By doing this, we have it that the vertex is at the point (3,72)
Thus, we can conclude that the maximum height the ball can reach is 72 ft
10 is not a multiple of 3 so no 6/10 is not multiples for 3/10 and 6 is not a mutiple of 10 so it can't be also the same with 6/30 although 6/30 is multiples for 3 but 6 is not a mutiple for 10.
