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aliya0001 [1]
2 years ago
9

How does the answer for this 09:009 is 10??

Mathematics
1 answer:
zysi [14]2 years ago
6 0
Hello,

0.09/0.009=(9/100) / (9/1000)=9/100 * 1000/9=10.
==================================

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The graph of f(x) is show below.
vlada-n [284]

ANSWER

(2,2)

EXPLANATION

Since f(x) and its inverse function are symmetric about the line y=x, if (a,b) lies on the graph of f, then (b,a) must lie on f inverse.

The point (2,2) lies on f and the same time on f inverse.

The solution is a point that satisfies both equations.

Hence the correct choice is:

(2,2)

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3 years ago
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The floor of Cara's living room is 10 feet by 14 feet. What is the area, in square feet, of the largest circular rug that can fi
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Answer:

78.5\ ft^{2}

Step-by-step explanation:

we know that

If the floor of Cara's living room is 10 feet by 14 feet

then

the diameter of the larger circular rug that can fit in Cara's living room is equal to 10 feet

<em>Find the area of the circular rug</em>

The area of the circle is equal to

A=\pi r^{2}

we have

r=10/2=5\ ft ----> the radius is half the diameter

\pi=3.14

substitute the values

A=(3.14)(5)^{2}=78.5\ ft^{2}

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3 years ago
Which function can be used to find the number of ounces of coffee in the can based on its radius?
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Answer:

A

Step-by-step explanation:

The answer is A I hope it helped!

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Assume a simple random sample of 10 BMIs with a standard deviation of 1.186 is selected from a normally distributed population o
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Answer:

a) H0: \sigma = 1.34

H1: \sigma \neq 1.34

b) df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

c) t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

d) For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

Step-by-step explanation:

Information provided

n = 10 sample size

s= 1.186 the sample deviation

\sigma_o =1.34 the value that we want to test

p_v represent the p value for the test

t represent the statistic  (chi square test)

\alpha=0.01 significance level

Part a

On this case we want to test if the true deviation is 1,34 or no, so the system of hypothesis are:

H0: \sigma = 1.34

H1: \sigma \neq 1.34

The statistic is given by:

t=(n-1) [\frac{s}{\sigma_o}]^2

Part b

The degrees of freedom are given by:

df = n-1= 10-1=9

And the critical values with \alpha/2=0.005 on each tail are:

\chi_{\alpha/2}= 1.735, \chi_{1-\alpha/2}= 23.589

Part c

Replacing the info we got:

t=(10-1) [\frac{1.186}{1.34}]^2 =7.05

Part d

For this case since the critical value is not higher or lower than the critical values we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true deviation is not significantly different from 1.34

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2 years ago
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klasskru [66]
The answer is B, 25 inches.
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