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Nuetrik [128]
2 years ago
9

The physical plant at the main campus of a large state university recieves daily requests to replace fluorescent lightbulbs. The

distribution of the number of daily requests is bell-shaped and has a mean of 52 and a standard deviation of 5. Using the empirical rule, what is the approximate percentage of lightbulb replacement requests numbering between 47 and 52
Mathematics
1 answer:
Bond [772]2 years ago
3 0

Answer:

34% of lightbulb replacement requests numbering between 47 and 52

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 52

Standard deviation = 5

Between 47 and 52:

52 is the mean and 47 is one standard deviation below the mean.

By the Empirical Rule, 68% of the measures are within 1 standard deviation of the mean.

Since the normal distribution is symmetric, of those, 34% are within 1 standard deviation below the mean and the mean(47 and 52) and 34% are within the mean and one standard deviation above the mean(52 and 57).

So

34% of lightbulb replacement requests numbering between 47 and 52

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Answer:

\sf \log_{10}6=0.7781

Step-by-step explanation:

<u>Given</u>:

\sf \log_{10} 2 = 0.3010

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To find log₁₀ 6, first rewrite 6 as 3 · 2:

\sf \implies \log_{10}6=\log_{10}(3 \cdot 2)

\textsf{Apply the log product law}: \quad \log_axy=\log_ax + \log_ay

\implies \sf \log_{10}(3 \cdot 2)=\log_{10}3+\log_{10}2

Substituting the given values for log₁₀ 3 and log₁₀ 2:

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Therefore:

\sf \log_{10}6=0.7781

Learn more about logarithm laws here:

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