Can someone help with this please?

Mathematics

1 answer:

lilavasa [31]4 years ago

5 0

Answer:

Step-by-step explanation:

hmu for an explanation

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Point A is located at (5, 10) and point B is located at (20, 25).

Alla [95]

Let's say the point is C, so C partitions AB into two pieces, where AC is at a ratio of 3 and CB is at a ratio of 7, thus 3:7,

$\bf \left. \qquad \right.\textit{internal division of a line segment}
\\\\\\
A(5,10)\qquad B(20,25)\qquad
\qquad 3:7
\\\\\\
\cfrac{AC}{CB} = \cfrac{3}{7}\implies \cfrac{A}{B} = \cfrac{3}{7}\implies 7A=3B\implies 7(5,10)=3(20,25)\\\\
-------------------------------\\\\
{ C=\left(\cfrac{\textit{sum of "x" values}}{\textit{sum of ratios}}\quad ,\quad \cfrac{\textit{sum of "y" values}}{\textit{sum of ratios}}\right)}\\\
-------------------------------$

$\bf C=\left(\cfrac{(7\cdot 5)+(3\cdot 20)}{3+7}\quad ,\quad \cfrac{(7\cdot 10)+(3\cdot 25)}{3+7}\right)
\\\\\\
C=\left( \cfrac{35+60}{10}~~,~~\cfrac{70+75}{10} \right)\implies C=\left(\cfrac{95}{10}~~,~~\cfrac{145}{10} \right)
\\\\\\
C=\left( \cfrac{19}{2}~~,~~\cfrac{29}{2} \right)\implies C=\left( 9\frac{1}{2}~~,~~14\frac{1}{2} \right)$

8 0

3 years ago

The first term of an arithmetic sequence is -3 and the 15th term is 53. What is the common difference of the sequence?

Fittoniya [83]

Answer:

c = 4

Step-by-step explanation:

Let the common difference be c. Then a(n) = -3 + c(n-1). Since a(15) = 53, a(15) = -3 + (15-1)c = 53. Therefore, -3 + 14c = 53, or 14c = 56; c = 4.

4 0

3 years ago

Idk how to do this. Please help

Nitella [24]