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QveST [7]
3 years ago
8

Pls help with 29 and 19

Mathematics
1 answer:
Phoenix [80]3 years ago
5 0
You should have written like this
1 hour /16 = x hour /100
x=100/16=25/4=6.25
but it asks how many hours after first hour
6.25-1=5.25
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This table shows the heights of four boxes that need to be mailed.
Ksenya-84 [330]
The answer to the question is B.
5 0
3 years ago
Give a geometric description of the following system of equations.a. 2x−4y=12 −3x+6y=−15.b. 2x−4y=12 −5x+3y=10.a. 2x−4y=12 −3x+6
Reptile [31]

Answer:

a. No solution, parallel lines.

b. One solution.

Step-by-step explanation:

Given the system of equations:

a. 2x-4y=12

-3x+6y=-15

b. 2x-4y=12

-5x+3y=10

To give a geometric description of the given system of equations.

The geometric description of a system of equations in 2 variables mean the system of equations will represent the number of lines equal to the number of equations in the system given.

i.e.

Number of planes = Number of variables

Number of lines = Number of equations in the system.

Here, we are given 2 variables and 2 equation in each system.

So, they can be represented in the xy-coordinates plane.

And the number of solutions to the system depends on the following condition.

Let the system of equations be:

A_1x+B_1y+C_1=0\\A_2x+B_2y+C_2=0

1. One solution:

There will be one solution to the system of equations,  If we have:

\dfrac{A_1}{A_2}\neq\dfrac{B_1}{B_2}

2. Infinitely Many Solutions: (Identical lines in the system)

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}= \dfrac{C_1}{C_2}

3. No Solution:(Parallel lines)

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}\neq\dfrac{C_1}{C_2}

Now, let us discuss the system of equations one by one:

a. 2x-4y=12 OR 2x-4y-12=0

-3x+6y=-15 OR -3x+6y+15=0

A_1 = 2, B_1 = -4, C_1 = -12\\A_2 = -3, B_2 = 6, C_2= 15

Here, the ratio:

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2} = -\dfrac{2}{3}\\\dfrac{C_1}{C_2} = -\dfrac{4}{5}

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}\neq\dfrac{C_1}{C_2}

Therefore, no solution i.e. parallel lines.

b. 2x-4y=12 OR 2x-4y-12=0

-5x+3y=10 OR -5x+3y-10=0

A_1 = 2, B_1 = -4, C_1 = -12\\A_2 = -5, B_2 = 3, C_2 = -10

\dfrac{A_1}{A_2}= -\dfrac{2}{5}\\\dfrac{B_1}{B_2} = -\dfrac{4}{3}\\\dfrac{C_1}{C_2} = -\dfrac{6}{5}

\dfrac{A_1}{A_2}\neq\dfrac{B_1}{B_2}

So, one solution.

Kindly refer to the images attached for the graphical representation of the given system of equations.

6 0
3 years ago
2×y to the power2<br> -6×y to the power 2
sertanlavr [38]
2y to the second power= 4y
-6y to the second power= -36y
4 0
3 years ago
Use a benchmark fraction to compare 7 10 ths and 5 12 ths. Explain how you found the answer
elixir [45]
<span>Benchmark fractions are created when we make two different fractions have the same numerator or denominator. In thisi case, we will produce the same denominator. The LCM of 10 and 12 is 60. So the fractions become 42/60 and 25/60. Since the fraction with the larger numerator has a larger value when the denominators are the same, 7/10 is larger than 5/12.</span>
5 0
3 years ago
Find the percent of the number: 64% 75
Dima020 [189]

64% of 75 = 64/100 x 75 = 48 <==== answer

4 0
3 years ago
Read 2 more answers
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