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photoshop1234 [79]
3 years ago
9

Selma spent 7/10 of her allowance on a new backpack. What percent of her allowance did she spend

Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
4 0
She spent 70% of her allowance
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Which of the following lists the order of operations in the correct order?
love history [14]

Answer:

whats the list

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
#1- Jennifer made a box plot to summarize this data. 124, 118, 129, 139, 133, 129, 142, 135, 122, 137. What is the median, the l
svp [43]

Answer:

B or

Lower quartile: 124

Median: 131

Upper quartile: 137

Step-by-step explanation:

To find the median first make the data in order from greatest to least:

118,122,124,129,129,133,135,137,139,142

Then find the middle 2 numbers which are 129 and 133

129+133=262 (divide by 2 to find average) so

median= 262/2=131

To find the Lower quartile find the number in the middle of the first 5 numbers which is 124

To find the Upper quartile find the number in the middle of the second 5 numbers which is 137 so

B or

Lower quartile: 124

Median: 131

Upper quartile: 137

8 0
3 years ago
If AC = 8x - 14 and EC = 2x + 11, solve for x.
Elan Coil [88]

Answer:

Step-by-step explanation:

8x-14=2x+11

-8 -8

-14=-6x+11

-11

-25=-6x

/-6

x=4.16

5 0
2 years ago
A single gram of a certain metallic substance has 0.52 g of copper and 0.25 g of zinc the remaining portion of the substance is
andrezito [222]
Ben's estimate gives 7 g of nickel; the actual amount is 8.03 g.

In 1 g of the substance, there is 0.52 g of copper and 0.25 g of zinc; this gives 
0.52+0.25 = 0.77 g of the substance.

The remaining part of the substance is nickel:
1-0.77 = 0.23 g of nickel.

Using Ben's estimate, 0.2 g of nickel per gram of substance, we have
0.2(35) = 7 g of nickel in 35 g of the substance.

The actual amount is 0.23(35) = 8.03 g of nickel in 35 g of the substance.
6 0
3 years ago
Suppose the heights of professional horse jockeys are normally distributed with a mean of 62 in. and a standard deviation of 2 i
ch4aika [34]
Mean = 62 in
SD = 2 in

At 16% = 0.16 and using Z tables,

Z≈ -0.99

x =(-0.99*2) + 62 ≈ 60 in

This represents jockeys who are shorter than 60 in.
6 0
3 years ago
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