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ser-zykov [4K]
3 years ago
10

What are the roots of this equation? Y=(x+2)(x-3)

Mathematics
1 answer:
max2010maxim [7]3 years ago
6 0
The roots of this equation can be found with 
(x+2)(x-3)=0  x+2=0 and <span>(x-3)=0 so x=-2 and x=3</span>
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What is the product?
LenaWriter [7]

Answer:

21x^{7}y^{11}

Step-by-step explanation:

Remove the parentheses and take out the constansts.

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Simplify 7 x 3 to 21.

21x^{2} x^{5} y^{3} y^{8}

Use the product rule: x^{a} x^{b} = x^{a + b}

21x^{2 + 5}y^{3+8}

Simplify 2+5 to 7.

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Simplfiy 3 + 8 to 11.

21x^{7}y^{11}

4 0
3 years ago
Evaluate the expression. Enter your answer in the box. 2³ =
masya89 [10]
2^3 = 2 x 2 x 2 = 8

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4 years ago
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Elza [17]

Answer:

5

Step-by-step explanation:

7 0
3 years ago
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ANTONII [103]

Answer:

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Consider x= -5 , y= -6

Now put value in to the equation

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3 0
3 years ago
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