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3 years ago

6th grade math, help pleasee:)

Mathematics

1 answer:

Kamila [148]3 years ago

7 0

Answer: a) v=12 feet

b) 1: 12

2: 24

3: 36

4: 48

Step-by-step explanation:

A) v=d/t

They give you 60 feet, which can be plugged in for d (distance), and 5 seconds which can be plugged into t (time).

So, v=60/5=12

B) Kendall runs 12 feet per second, so in the chart:

1 sec x 12 feet = 12 feet

2 sec x 12 feet = 24 feet

3 sec x 12 feet = 36 feet

4 sec x 12 feet = 48 feet

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6 groups of students sell 162 balloons at the school carnival. there are 3 students in each group. if each student sells the sam

Serga [27]

They have enough balloons because I used division as my operation. 3 can go into 16 five times. I got 1 after subtracting and bring down 2. 3 can go into 12 evenly 4 times. 12 minus 12 equals 0 with no remainder. So, they get 54 balloons for each group. But I want to know how many EACH student gets enough balloons. 54 divided by 6 groups equals 9 balloons for each student. GLOSSARY: Division - Set of operation that breaks down numbers into equal parts | Remainder - left over ||

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3 years ago

Read 2 more answers

Do you know how to find rate of change? X&Y intercepts? Zeros?

Rzqust [24]

#Rate of change

Rate of change is slope

If two points be (x1,y-1) and (X2,Y2) then

Slope=m=y_2-y_1/x_2-x_1

If a line be ax+by+c=0

m=-a/b

#X and y inetercept

If a equation given y=mx+b

To find x intercept put y=0
To find y inetercept put x=0

#Zeros

To find the zeros spot out the x inetercepts

The x values of the x intercepts are the zeros

3 0

3 years ago

Would each situation be represented by a positive or a negative number?

insens350 [35]

If 2 sodas and 4 hamburgers are $12.00 and 4 sodas and 2 hamburgers are $9.00 how much is a single hamburger?
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

2s + 4h = 12, (1) 4s + 2h = 9. (2) Multiply (1) by 2. You will get 4s + 8h = 24, (1') 4s + 2h = 9. (2') Distract (2') from (1'). You will get 8h - 2h = 24 - 9, or 6h = 15 ---> h = = = 2.5. Thus one hamburger price is $2.50. Then from (1) s = = 1. Answer. One hamburger price is $2.50 and 1 soda costs $1.00.

There is even more elegant way to solve the problem.

Simply add all hamburgers and all sodas. 6 hamburgers and 6 sodas. $12 + $9 = $21.

Hence, 1 hamburger + 1 soda = = $3.50.

Having this, everybody can solve to the end in this way, actually, without equations and using the mental math only.

Question: A man measures the angle of elevation to the top of a mountain to be 12 degrees. He drives 7 miles closer and finds the angle of elevation to be 37 degrees. How high is the mountain?

5 0

4 years ago

Find the solution to the differential equation dB/dt+4B=20 with B(1)=30

natita [175]

Answer:

The solution of the differential equation is $B=5+25e^{-4t+4}$

Step-by-step explanation:

The differential equation $\frac{dB}{dt}+4B=20$ is a first order separable ordinary differential equation (ODE). We know this because a separable first-order ODE has the form:

$y'(t)=g(t)\cdot h(y)$

where g(t) and h(y) are given functions.

We can rewrite our differential equation in the form of a first-order separable ODE in this way:

$\frac{dB}{dt}+4B=20\\\frac{dB}{dt}=20-4B\\\frac{dB}{dt}=4(5-B)\\\frac{1}{5-B}\frac{dB}{dt}=4$

Integrating both sides

$\frac{1}{5-B}\frac{dB}{dt}=4\\\frac{1}{5-B}\cdot dB=4\cdot dt\\\\\int\limits {\frac{1}{5-B}} \, dB=\int\limits {4} \, dt$

The integral of left-side is:

$\int\limits {\frac{1}{5-B}} \, dB\\\mathrm{Apply\:u-substitution:}\:u=5-B\\\int\limits {\frac{1}{5-B}} \, dB=\int\limits {\frac{1}{u}} \, dB\\\mathrm{du=-dB}\\-\int\limits {\frac{1}{u}} \,du\\\mathrm{Use\:the\:common\:integral}:\quad \int \frac{1}{u}du=\ln \left(\left|u\right|\right)\\-\int\limits {\frac{1}{u}} \,du =-\ln \left|u\right|\\\mathrm{Substitute\:back}\:u=5-B\\-\ln \left|5-B\right|\\\mathrm{Add\:a\:constant\:to\:the\:solution}\\-\ln \left|5-B\right|+C$

The integral of right-side is:

$\int\limits {4} \, dt = 4t + C$

We can join the constants, and this is the implicit general solution

$-\ln \left|5-B\right|+C=4t + C\\-\ln \left|5-B\right|=4t + D$

If we want to find the explicit general solution of the differential equation

We isolate B

$-\ln \left|5-B\right|=4t + D\\\ln \left|5-B\right|=-4t+D\\\left|5-B\right|=e^{-4t+D}$

Recall the definition of |x|

$|x|=\left \{ {{x, \:if \>x\geq \>0 } \atop {-x, \:if \>x0}} \right.$

$\left|5-B\right|=e^{-4t+D}\\5-B= \pm \:e^{-4t+D}\\B=5 \pm \:e^{-4t+D}\\B=5\pm \:e^{-4t}\cdot e^{D}\\B=5+Ae^{-4t}$

where $A=\pm e^{D}$

Now B(1) =30 implies

$B=5+Ae^{-4t}\\30=5+Ae^{-4}\\30-5=Ae^{-4}\\25e^{4}=A$

And the solution is

$B=5+(25e^{4})e^{-4t}\\B=5+25e^{-4t+4}$

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4 years ago

Make up two polynomial functions, f of x and g of x.

Cloud [144]

Answer:

The remainder theorem states that when a polynomial, f(x), is divided by a linear polynomial , x - a, the remainder of that division will be equivalent to f(a). ... It should be noted that the remainder theorem only works when a function is divided by a linear polynomial, which is of the form x + number or x Step-by-step explanation:

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3 years ago