So we are given an initial equation of:
.
We are told that a new path is going to be perpendicular to this line. So to find a slope that is perpendicular to a line, we take the slope of the known line (in this case 2) and we flip it and change the sign. So since this slope is essentially
, we are going to flip it to make it
and change the sign to make it
.
So now we know that the slope of the perpendicular line is
, we can start a new equation for this line:

We are also told that the path will intersect at (-2,-3) - this is a solution to the two lines. So to find b in this new equation, let's plug in the x and y values found in the point:

Then solve for b:


So then we plug in our value for b and leave x and y:

So this equation now represents the new path.
Answer:
5ab + 8 - 1a^2.
Step-by-step explanation:
Combining like terms, we get 3a^2 - 4a^2 = -1a^2. We get 9ab - 4ab = 5ab. Then we get, 5 + 3 = 8. Together this is 5ab + 8 - 1a^2
The answer is -1.5+(-2.75)=-4.25. This equation is the same as the result of -1.5 -2.75.
the x-intercept is the point where the line touches the x-axis. The x-intercept is (4,0)
the y-intercept is the point where the line touches the y-axis. The y-intercept is (0,-2)