I’m a little confused by the question and the problem, is there a picture of the problem you could add?
Let's simplify step-by-step.<span><span><span>12+<span><span>8x</span><span>(<span>4+3</span>)</span></span></span>+2</span>−6</span><span>=<span><span><span><span>12+<span>56x</span></span>+2</span>+</span>−6
</span></span>Combine Like Terms:<span>=<span><span><span>12+<span>56x</span></span>+2</span>+<span>−6</span></span></span><span>=<span><span>(<span>56x</span>)</span>+<span>(<span><span>12+2</span>+<span>−6</span></span>)</span></span></span><span>=<span><span>56x</span>+8
</span></span>Answer:<span>=<span><span>56x</span>+<span>8
Good luck mate :P</span></span></span>
Answer:
B
Step-by-step explanation:
16,x+4
by completing square formula
B is the answer I know because I took the test
Note: Consider we need to find the vertices of the triangle A'B'C'
Given:
Triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C'.
Triangle A,B,C with vertices at A(-3, 6), B(2, 9), and C(1, 1).
To find:
The vertices of the triangle A'B'C'.
Solution:
If triangle ABC is rotated 90 degrees clockwise about the origin to create triangle A'B'C', then
Using this rule, we get
Therefore, the vertices of A'B'C' are A'(6,3), B'(9,-2) and C'(1,-1).
