The frequency of the second class is 6.
Since the class width is 6 and the lower limit of the first class is 50, this means the first class goes from 50-55. This would put the second class at 56-61. There are 6 data points in this set that would go in the second class.
Answer:
I. Base area = 35 cm²
II. Volume of rectangular prism = 350 cm³
Step-by-step explanation:
Given the following data;
Length = 7cm
Breadth = 5cm
Height = 10cm
a. To find the base area of the rectangular prism;
Base area = length * breadth
Base area = 7 * 5
Base area = 35 cm²
b. To find how much it takes to fill the rectangular prism, we would need to determine its volume.
Volume of rectangular prism = length * breadth * height
Volume of rectangular prism = 7 * 5 * 10
Volume of rectangular prism = 350 cm³
c. To find the answers to the other part of the question, we would determine the capacity of the prism in litres.
Capacity = volume in cm³ to litres
1 centimeter = 0.001 litres
Capacity = 350 * 0.001
Capacity = 0.35 litres.
Answer:
12-4√5
Step-by-step explanation:
(√10-√2)²
(√10-√2)(√10-√2)
Foil/distribute
10-√20-√20+2
12-2√20
12-2√4*√5
12-2*2√5
12-4√5
If the mean is 20.8, one standard deviation each way is adding and subtracting 3.1, so 17.7 and 23.9 (68% of values)
Two standard deviations adding and subtracting 3.1*2 = 6.2, or 14.6 and 27.
Three standard deviations is 11.5 and 30.1
So we have
11.5 - 14.6 - 17.7 - 20.8 - 23.9 - 27 - 30.1
Going left to 11.5 is 3 standard deviations out, so 99.7/2 = 49.85%
Going right to 27 is 2 standard deviations out, so 95/2 = 47.5%
Add those two % to get 97.32%
This is hard to do without a picture so I hope that helps!
Answer:
x=16/113
Step-by-step explanation:
look at them in order
