All categories

3 years ago

The sum of two numbers is 25. One of he numbers exceeds the other by 9. Find the numbers

2 answers:

3 0

X + y = 25
x is the smaller number.
y is the smaller number plus 9 (x + 9).

x + (x + 9) = 25
2x + 9 = 25
2x = 16
x = 8

8 + y = 25
y = 17

The numbers are 8 and 17.

lapo4ka [179]3 years ago

3 0

X and y are the numbers
sum is 25 so
x+y=25

x is bigger than y by 9
x=y+9
subsitue y+9 for x

x+y=25
y+9+y=25
2y+9=25
minus 9 both sides
2y=16
divide by 2
y=8

sub back
x=y+9
x=8+9
x=17

the numbers are 8 and 17

You might be interested in

Winston is making steaks for his 4 friends. If each steak is 7.7 oz, how much steak is Winston making? Choices are:

sattari [20]

Answer:D

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

A rectangular field has an area of 162 m2.

Fed [463]

Answer:Length: 27m

Step-by-step explanation:

the formula of area of rectangle is : width*length
so we just replace the values in the formula
162=6*Length
Length=162/6
Length=27m

3 0

3 years ago

Read 2 more answers

Help will mark Brainliest!!

Marta_Voda [28]

Answer:

1/20

Step-by-step explanation:

1/4 = 0.25

0.25 / 5 = 0.05

0.05 as a fraction = 5/100

simplified

5 / 5 = 1

100 / 5 = 20

1/20

5 0

2 years ago

Find the measure of angle 6

Veseljchak [2.6K]

Unless you show a picture, its impossible to solve.

5 0

3 years ago

Read 2 more answers

Describe the translation of the function from the parent function f(x) = x².

kkurt [141]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\

\end{array}\\$

$\bf \begin{array}{llll}
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}
$

now, notice the template above... now let's see your function $\bf y=x^2+4\implies 
\begin{array}{llllll}
y=&1(&1x&+&0)^2+&4\\
&A&B&&C&D
\end{array}$

so.. what do you think was the shift then?

8 0

3 years ago