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3 years ago

What is the area of the shaded part ? Take(π=22/7)

Mathematics

1 answer:

sergiy2304 [10]3 years ago

5 0

Answer:

Given:

radius of bigger half circle[R]=(7+7+14)/2=14cm

radius of smaller half circle [r]=14/2=7cm

Area of shaded region =1/2[πR² -πr²]

=1/2×22/7×[14²-7²]=231cm²

Area of shaded region=231cm²

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What are the domain and range of the function?<br> f(x) = ^3 square x - 3

DerKrebs [107]

Step-by-step explanation:

$f(x) = \sqrt[3]{x - 3}$

The domain of a function are the values of $x$ that you can plug into the function $f(x)$ .

Values inside of a root must be non-negative, which means that $x - 3$ must be greater than or equal to zero. We can set up an equation to find the domain:

$x - 3 \geq 0$

$x \geq 3$

With this, we know the domain of the function is $[3, \inf)$ .

The range of a function are the values that $f(x)$ can have. Since the equation is a cube root, the value will always be non-negative, meaning the range of the function is $[0, \inf)$ .

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3 years ago

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Step-by-step explanation:

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3 years ago

The International Air Transport Association surveys business travelers to develop quality ratings for transatlantic gateway airp

motikmotik

Answer:

The 95% confidence interval for the population mean rating is (5.73, 6.95).

Step-by-step explanation:

We start by calculating the mean and standard deviation of the sample:

$M=\dfrac{1}{n}\sum_{i=1}^n\,x_i\\\\\\M=\dfrac{1}{50}(6+4+6+. . .+6)\\\\\\M=\dfrac{317}{50}\\\\\\M=6.34\\\\\\s=\sqrt{\dfrac{1}{n-1}\sum_{i=1}^n\,(x_i-M)^2}\\\\\\s=\sqrt{\dfrac{1}{49}((6-6.34)^2+(4-6.34)^2+(6-6.34)^2+. . . +(6-6.34)^2)}\\\\\\s=\sqrt{\dfrac{229.22}{49}}\\\\\\s=\sqrt{4.68}=2.16\\\\\\$

We have to calculate a 95% confidence interval for the mean.

The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.

The sample mean is M=6.34.

The sample size is N=50.

When σ is not known, s divided by the square root of N is used as an estimate of σM:

$s_M=\dfrac{s}{\sqrt{N}}=\dfrac{2.16}{\sqrt{50}}=\dfrac{2.16}{7.071}=0.305$