Question

Which is equivalent to (9 y squared minus 4 x)(9 y squared + 4 x), and what type of special product is it? 81 y Superscript 4 Baseline minus 16 x squared, a perfect square trinomial 81 y Superscript 4 Baseline minus 16 x squared, the difference of squares 81 y Superscript 4 Baseline minus 72 x y squared minus 16 x squared, a perfect square trinomial 81 y Superscript 4 Baseline minus 72 x y squared minus 16 x squared, the difference of squares

Answer 1

Answer:

Option B 81 y Superscript 4 Baseline minus 16 x squared, the difference of squares is correct.

Step-by-step explanation:

We need to solve:

(9y^2 -4x)(9y^2+4x)

Finding the product:

9y^2(9y^2+4x) -4x(9y^2+4x)

81y^4+36y^2x-36y^2x-16x^2

81y^4 - 16x^2

Type of Special product

The product is differences of square because

81y^4 = (9y^2)^2

and 16x^2 = (4x)^2

So, 81y^4 - 16x^2 =  (9y^2)^2 - (4x)^2

Hence Option B 81 y Superscript 4 Baseline minus 16 x squared, the difference of squares is correct.

Answer 2

Answer:

Option B 81 y Superscript 4 Baseline minus 16 x squared, the difference of squares is correct.

Step-by-step explanation:

We need to solve:

(9y^2 -4x)(9y^2+4x)

Finding the product:

9y^2(9y^2+4x) -4x(9y^2+4x)

81y^4+36y^2x-36y^2x-16x^2

81y^4 - 16x^2

Type of Special product

The product is differences of square because

81y^4 = (9y^2)^2

and 16x^2 = (4x)^2

So, 81y^4 - 16x^2 =  (9y^2)^2 - (4x)^2

Hence Option B 81 y Superscript 4 Baseline minus 16 x squared, the difference of squares is correct.

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Step-by-step explanation: