Answer:
Option B 81 y Superscript 4 Baseline minus 16 x squared, the difference of squares is correct.
Step-by-step explanation:
We need to solve:
(9y^2 -4x)(9y^2+4x)
Finding the product:
9y^2(9y^2+4x) -4x(9y^2+4x)
81y^4+36y^2x-36y^2x-16x^2
81y^4 - 16x^2
Type of Special product
The product is differences of square because
81y^4 = (9y^2)^2
and 16x^2 = (4x)^2
So, 81y^4 - 16x^2 = (9y^2)^2 - (4x)^2
Hence Option B 81 y Superscript 4 Baseline minus 16 x squared, the difference of squares is correct.
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Step-by-step explanation: