First, you have to find the moment of inertia along the x and y axes. Constant density is denoted as k.


Then, the radii of gyration for
x = √[I_x/m]
y = [I_y/m]
where m = k(15-4)² = 121k. Then,
x = y = [4880.33k/121k] = 40.33
I hope I was able to help you. Have a good day.
I think $43.57 Bc 41.90 times .04 is 16.76 then move the decimal, and add 41.90+1.67=43.57
Answer:
- 18x + 15y ≤ 300
- x ≥ 0; y ≥ 6
Step-by-step explanation:
Variables are defined in the problem statement.
18x +15y ≤ 300 . . . . total budget
y ≥ 6 . . . . . . . . . . . . minimum number of annuals
x ≥ 0 . . . . . number of perennials cannot be negative
This system of inequalities describes the situation.
Answer:
Step-by-step explanation:
if center=(h,k)
radius=r
eq. of circle is (x-h)^2+(y-k)^2=r^2
given eq. is (x-5)^2+(y+2)^2=16=4^2
comparing
center =(5,-2)
radius r=4
Answer:
B. 9x10^4
Step-by-step explanation:
