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2 years ago

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On Saturday,a library checked out 52 books, if 24 of the books were fiction what is the ratio of non fiction ion to fiction book

s checked out

1 answer:

Alex787 [66]2 years ago

3 0

76 were fiction in the libarsry

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A rectangular lamina of uniform density is situated with opposite corners at (0,0) and (15,4). calculate its radii of gyration a

Sphinxa [80]

First, you have to find the moment of inertia along the x and y axes. Constant density is denoted as k.

$I_{x}= \int\limits^15_0\int\limits^4_0 {k y^{2} } \, dx dy= \frac{1}{3}k (15-4)^4=4880.33k$

$I_{y}= \int\limits^15_0\int\limits^4_0 {k x^{2} } \, dx dy= \frac{1}{3}k (15-4)^4=4880.33k$

Then, the radii of gyration for

x = √[I_x/m]
y = [I_y/m]

where m = k(15-4)² = 121k. Then,

x = y = [4880.33k/121k] = 40.33

I hope I was able to help you. Have a good day.

7 0

2 years ago

Last week Bill made a purchase of $56.78 before tax. This week, the same items on sale would have cost him $41.90 before tax. If

olga2289 [7]

I think $43.57 Bc 41.90 times .04 is 16.76 then move the decimal, and add 41.90+1.67=43.57

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2 years ago

Read 2 more answers

Travis has a budget of $300 that he can spend on perennial flowers and at least 6 annual flowers. Perennial flowers are 18 dolla

boyakko [2]

Answer:

18x + 15y ≤ 300
x ≥ 0; y ≥ 6

Step-by-step explanation:

Variables are defined in the problem statement.

18x +15y ≤ 300 . . . . total budget

y ≥ 6 . . . . . . . . . . . . minimum number of annuals

x ≥ 0 . . . . . number of perennials cannot be negative

This system of inequalities describes the situation.

6 0

2 years ago

What is the center and radius of the following circle (x - 5) ^ 2 + (y + 2) ^ 2 = 16

murzikaleks [220]

Answer:

Step-by-step explanation:

if center=(h,k)

radius=r

eq. of circle is (x-h)^2+(y-k)^2=r^2

given eq. is (x-5)^2+(y+2)^2=16=4^2

comparing

center =(5,-2)

radius r=4

4 0

2 years ago

Which shows the expression below in simplified form?

statuscvo [17]

Answer:

B. 9x10^4

Step-by-step explanation:

$\frac{4.5 \times {10}^{8} }{5 \times {10}^{3} } \\ = 0.9 \times {10}^{8 - 3} \\ = 0.9 \times {10}^{5} \\ = 9 \times {10}^{4}$

5 0

2 years ago