The probability that the contestant wins at least one car is 3/5.
<h3>What is the probability?</h3>
Probability refers to a possibility that deals with the occurrence of random events.
The probability of all the events occurring need to be 1.
For 1 car, we consider two possible outcomes:
P(1 car) = 2/6 x 4/5 + 4/6 x 2/5
P(1 car) = 8/15
For no car in either door
P(no car) = 4/6 x 3/5
P(no car) = 2/5
The probability that the contestant wins at least one car is the sum of the probability of one car and the probability of two cars:
P(2 cars) = 2/6 x 1/5
= 1/15
P(1 car) + P(2 cars) = 8/15 + 1/15
= 3/5
Learn more about probability here;
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Answer:
Step-by-step explanation:
(0, 1) (4, -2)
(-2 - 1)/(4 -0) = -3/4
Answer:
141 but i am prolly wrong
Step-by-step explanation:
Step-by-step explanation:
If x=3, y=7 when x+y=z
z=3+7
z=10
Answer:
titutex=cos\alp,\alp∈[0:;π]
\displaystyle Then\; |x+\sqrt{1-x^2}|=\sqrt{2}(2x^2-1)\Leftright |cos\alp +sin\alp |=\sqrt{2}(2cos^2\alp -1)Then∣x+
1−x
2
∣=
2
(2x
2
−1)\Leftright∣cos\alp+sin\alp∣=
2
(2cos
2
\alp−1)
\displaystyle |\N {\sqrt{2}}cos(\alp-\frac{\pi}{4})|=\N {\sqrt{2}}cos(2\alp )\Right \alp\in[0\: ;\: \frac{\pi}{4}]\cup [\frac{3\pi}{4}\: ;\: \pi]∣N
2
cos(\alp−
4
π
)∣=N
2
cos(2\alp)\Right\alp∈[0;
4
π
]∪[
4
3π
;π]
1) \displaystyle \alp \in [0\: ;\: \frac{\pi}{4}]\alp∈[0;
4
π
]
\displaystyle cos(\alp -\frac{\pi}{4})=cos(2\alp )\dotscos(\alp−
4
π
)=cos(2\alp)…
2. \displaystyle \alp\in [\frac{3\pi}{4}\: ;\: \pi]\alp∈[
4
3π
;π]
\displaystyle -cos(\alp -\frac{\pi}{4})=cos(2\alp )\dots−cos(\alp−
4
π
)=cos(2\alp)…
1
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