Question

A square is inscribed in an isosceles right triangle. Length of the leg equals to 2 in. as shown on the figure. Find the perimeter of the square.

Answer 1

Answer:

The perimeter of the square is $4\ in$

Step-by-step explanation:

Let

x----> the length side of the square

we know that

In an isosceles right triangle the measures of the internal angles are 45°-90°-45°

so

the horizontal distance is equal to the vertical distance

$2=x+x$

$x=1\ in$

The perimeter of the square is

$P=4b$

we have

$b=1\ in$

substitute

$P=4(1)=4\ in$