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WARRIOR [948]
2 years ago
8

HELP PLZ

Mathematics
1 answer:
djverab [1.8K]2 years ago
6 0

Answer:

no 12,5,12

Step-by-step explanation:

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Answer:

x=33 and y= 75 is the answer.

7 0
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Hello I need help on this question. :)
iris [78.8K]

Answer:

C

(4)+8 = 3(4)

12=12

Step-by-step explanation:

7 0
3 years ago
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Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .
lions [1.4K]

Formula for the area of a quarter circle: A = (pi x r^2) / 4

A = (3.14 x 36) / 4

A = 113.04 / 4

A = 28.26 square feet

Hope this helps! :)

6 0
3 years ago
Read 2 more answers
1. Sand falling from a chute forms a conical pile whose altitude is always equal to 4/3 the radius of the base. (a) How fast is
solong [7]

Answer:

The volume is increasing at a rate of 16286 in³/min.

Step-by-step explanation:

a) The volume of a cone is given by:

V = \frac{1}{3}h\pi r^{2}

Where:    

r: is the radius

h: is the height

The rate of change of the volume can be calculated by using the chain rule:

\frac{dV}{dt} = \frac{\pi}{3}[\frac{dh}{dt}r^{2} + h\frac{d(r^{2})}{dt}]

Since h = 4/3 r we have:

\frac{dV}{dt} = \frac{\pi}{3}[\frac{d(\frac{4r}{3})}{dt}r^{2} + \frac{4r}{3}\frac{d(r^{2})}{dt}]

\frac{dV}{dt} = \frac{4\pi}{9}[\frac{dr}{dt}r^{2} + r\frac{d(r^{2})}{dt}]        

\frac{dV}{dt} = \frac{4\pi}{9}[\frac{dr}{dt}r^{2} + 2r^{2}\frac{dr}{dt}]    (1)    

With:

\frac{dr}{dt} = 3 in/min

r = 3 ft*\frac{12 in}{1 ft} = 36 in

And by entering the above values into equation (1) we have:

\frac{dV}{dt} = \frac{4\pi}{9}[(3 in/min)*(36 in)^{2} + 2*(36 in)^{2}*3 in/min]

\frac{dV}{dt} = 16286 in^{3}/min

Therefore, the volume is increasing at a rate of 16286 in³/min.

I hope it helps you!                                    

3 0
3 years ago
Solve systems of equations for x + y, please!! -5x + 3y = 2 -5x - 5y = -30
dangina [55]
X,y=(123/20,1/4)



explanation
-5x+3y=-30
2-5x-5y=-30
-5x+3y=-30
-5x-5y=-32
-5x+3y=30
5x+5y=32
8y=2
y=1/4
-5x+3x1/4=-30
x=123/20
4 0
3 years ago
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