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3 years ago

Janae has 280 dimes in her piggy bank she has 10 times as many pennies how many pennies does Janae have

Mathematics

1 answer:

Natalija [7]3 years ago

8 0

Answer:

She has 28 pennies

Step-by-step explanation:

Janae has 280 dimes in her piggy bank she has 10 times as many pennies .

If she has 280 dimes in piggy bank

And has 10 times as many pennies

Let dimes= x

Let pennies= y

X= 10y

But x= 280

280= 10y

280/10 = y

28 = y

She has 28 pennies

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In ACME PUBLISHING SWEEPSTAKES, the chance of winning a car is 1 in 1,000. What percent of tickets to ACME PUBLISHING SWEEPSTAKE

Yuri [45]

Answer:

0.1% of tickets to ACME PUBLISHING SWEEPSTAKES win a car

Step-by-step explanation:

Given :The chance of winning a car is 1 in 1,000.

To Find : What percent of tickets to ACME PUBLISHING SWEEPSTAKES win a car?

Solution:

The chance of winning a car is 1 in 1,000.

The percent of tickets to ACME PUBLISHING SWEEPSTAKES win a car:

= $\frac{1}{1000} \times 100$

= $\frac{1}{10}$

= $0.1\%$

Hence 0.1% of tickets to ACME PUBLISHING SWEEPSTAKES win a car.

8 0

2 years ago

If the distribution is really (5.43,0.54)

defon

Answer:

0.7486 = 74.86% observations would be less than 5.79

Step-by-step explanation:

I suppose there was a small typing mistake, so i am going to use the distribution as N (5.43,0.54)

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The general format of the normal distribution is:

N(mean, standard deviation)

Which means that:

$\mu = 5.43, \sigma = 0.54$