1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sdas [7]
3 years ago
10

Pls answer this question im confused

Mathematics
1 answer:
expeople1 [14]3 years ago
6 0

Answer:

D) 0.05, 0.0516, 16%, \frac{5}{16}, 5.16

Step-by-step explanation:

Convert the factions and percentages to decimals to solve the problem quickly. Then, put them least to greatest.

Example: \frac{5}{16} is 0.3125 and 16% is 0.16.

You might be interested in
What is the equation of a line that passes through the points (3,6) and (8,4)?
Semmy [17]

Answer:

= x-

27

y-x-2

y=-3x-24

y=-x+

36

5

Step-by-step explanation:

3 0
3 years ago
Cathrine was concerned about her report card grade. She had 5 tests the whole semester. If her scores on each test were 93, 82,
enyata [817]

Answer:

81.6

Step-by-step explanation:

mean/average of her grade = sum of all scores/the number of scores

= (93+82+74+92+67)/5

= 81.6

4 0
3 years ago
This is worth 18 points to whoever gets it right and also if you do get it right first you'll get voted as brainlyess answrr
Bumek [7]
The correct answer is <span>1 and 1/2

Hope I helped</span>
4 0
3 years ago
Read 2 more answers
Among 9 electrical components exactly one is known not to function properly. if 4 components are randomly selected, find the pro
seraphim [82]

Answer:

0.4444

Step-by-step explanation:

Use the following property to ease the calculation:

P(At least one)=1-P(None)

Total number of electrical components: 9

Number that does not function well :1

Number that functions well : 8

We have ^8C_4=70 ways to to choose 4 good components from 8.

We have ^9C_4=126 ways to choose 4 components from a total of 9.

If all function properly then none is bad, we ^1C_0=1 way to do this.

P(At least one)=1-\frac{^8C_4*^1C_0}{^9C_4}

P(At least one)=1-\frac{70*1}{126}

P(At least one)=0.4444

4 0
3 years ago
Read 2 more answers
Illinois license plates used to consist of either three letters followed by three digits or two letters followed by four digits.
DENIUS [597]

Answer:

The probability that a randomly chosen plate contains the number 2222 is 0.000028 approximately.

The probability that a randomly chosen plate contains the sub-string HI is 0.002548  approximately.

Step-by-step explanation:

Consider the provided information.

Illinois license plates used to consist of either three letters followed by three digits or two letters followed by four digits.

Part (A)

Let A is the ways in which plates consist of three letters followed by three digits and B is the ways in which two letters followed by four digits.

Here repetition is allow. The number of alphabets are 26 and the number of distinct digits are 10.

The numbers of ways in which three letters followed by three digits can be chosen is: 26\times 26\times 26 \times 10 \times 10 \times10

26^3\times 10^3=17576000

The numbers of ways in which two letters followed by four digits can be chosen is: 26\times 26\times 10 \times 10 \times 10 \times10

26^2\times 10^4=6760000

Hence, the total number of ways are 17576000 + 6760000 = 24336000

Randomly chosen plate contains the number 2222 that means the first two letter can be any alphabets but the rest of the digit should be 2222.

Thus, the total number of ways that a randomly chosen plate contains the number 2222 number are: 26^2=676

The probability that a randomly chosen plate contains the number 2222 is:

\frac{676}{24336000} \approx 0.000028

Part (B)

The number of ways in which chosen plate contains the sub-string HI:

If three letters followed by three digits plate contains the sub-string HI, then the number of possible ways are:

26\times 1\times10^3+1\times 26\times10^3

If two letters followed by four digits plate contains the sub-string HI, then the number of possible ways are:

1\times 10^4

Thus, the total number of ways that a randomly chosen plate contains the sub-string HI are:

1\times 10^4+26\times 1\times10^3+1\times 26\times10^3

62000

From part (A) we know that the total number of ways to chose a number plate is 24336000.

The probability that a randomly chosen plate contains the sub-string HI is:

\frac{62000}{24336000} \approx 0.002548

7 0
3 years ago
Other questions:
  • Following diagram find the missing measure.
    8·1 answer
  • Darci wants to buy a computer that
    10·2 answers
  • How to change one third into twelfths
    7·2 answers
  • The hang time of a basketball player who jumps a verticle distance of 2 feet (0.6m) is 2/3 seconds. What will be the hang time i
    9·1 answer
  • After an election in a small town, the newspaper reported that 42% of the registered voters actually voted. If 12,000 people vot
    8·1 answer
  • What tools did the Greeks not use in the geometric constructions?
    10·2 answers
  • Find all the complex square roots of w= 36(cos60°+ isin60°). Write the roots in polar form with θ in degrees.
    14·1 answer
  • Can anyone help to answer my previous questions?
    15·1 answer
  • I need help can someone pls help me I need to get this right for my test :((!
    10·1 answer
  • 5. a number from 1-50 is chosen at random.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!