The derivative of a variable raised to exponent of n, x^n is equal to the product of n and x raised to exponent of n-1.
d(x^n) = (n)(x^n-1)
So, from the given
d(9x + 5) = (1)(9x^1-0) + 5(0)
= 9
The given value of x is irrelevant to this item because the derivative does not contain any variable x.
Answer:
y+3=-6(x+8)
Step-by-step explanation:
Because we already know a point and the slope, we can put our equation in the form y-y1=m(x-x1);
y+3=-6(x+8)
Answer:
θ =
(60° )
Step-by-step explanation:
Using the identity
sin²x + cos²x = 1 ⇒ sin²x = 1 - cos²x
Given
cos²θ - sin²θ = 2 - 5cosθ
cos²θ - (1 - cos²θ) = 2 - 5cosθ
cos²θ - 1 + cos²θ = 2 - 5cosθ
2cos²θ - 1 = 2 - 5cosθ ( subtract 2 - 5cosθ from both sides )
2cos²θ + 5cosθ - 3 = 0 ← in standard form
(cosθ + 3)(2cosθ - 1) = 0 ← in factored form
Equate each factor to zero and solve for θ
cosθ + 3 = 0
cosθ = - 3 ← not possible as - 1 ≤ cosθ ≤ 1
2cosθ - 1 = 0
cosθ =
, so
θ =
(
) =
( or 60° )
It is x^4 - y^2
so, expanding it, (x^2-y)(x^2+y)
hope it served