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3 years ago

I need help my question is -2 less than or equal to 3x-2 <10

Mathematics

1 answer:

Kisachek [45]3 years ago

4 0

A n s w e r:

0 ≤ x < 4

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An investor has an account with stock from two different companies. Last year, her stock in Company A was worth $5990 and her st

GenaCL600 [577]

Answer: 14.38%

Step-by-step explanation:

Worth of stock in Company A = $5990

Percent decrease = 20%

New worth = $5990 - (20% × $5990)

= $5990 - (0.2 × $5990)

= $5990 - $1198

= $4972

Worth of stock in Company B = $2450

Percent decrease = 8%

New worth = $2450 - (8% × $2450)

= $2450 - (0.08 × $2450)

= $2450 - $196

= $2254

Previous total worth = $5990 + $2450

= $8440

Total worth = $4972 + $2254

= $7226

The total percentage decrease in the investor's stock account will be:

= [($8440 - $7226) / $8440] × 100

=( $1214 / $8440) × 100

= 0.1438 × 100

= 14.38%

3 0

3 years ago

Read 2 more answers

If the point (2,-5) is reflected in the line y=x, then the image is what? { this is about reflections btw}

nikitadnepr [17]

In this question the answer is C

hope this helped

4 0

3 years ago

What is the product? 2y/y-3 multiplied by 4y-12/2y+6

Tasya [4]

<h2>Answer:</h2>

The answer is $\frac{4y}{y+3}$

<h2>Step-by-step explanation:</h2>

See the attached figure

7 0

3 years ago

Read 2 more answers

The demand function for q units of a product at $p per unit is given by p(q + 3)2 = 100,000. Find the rate of change of quantity

wariber [46]

Answer:

-0.625 unit

Step-by-step explanation:

Given that:

$p(q+3)^2 = 100, 000$

where;

p = price

q = quantity

To find the rate of change of quantity (q) with respect to price (p) we go by the differentiation

$(q+3)^2\frac{dp}{dp} +p^2(q+3)\frac{dq}{dp}=0$

$(q+3)^2 +p^2(q+3)\frac{dq}{dp}=0$

$\frac{dq}{dp}=\frac{-(q+3)}{2p}$

when P =40

Then 4(q+3)² = 100, 000

(q+3)² = $\frac{100,000}{4}$

(q+3)² = 25,000

(q+3) = $\sqrt{2500}$

q+ 3 = 50

q = 50 -3

q = 47

NOW; $\frac{dq}{dp}=\frac{-(q+3)}{2p}$

$\frac{dq}{dp}=\frac{-(47+3)}{2*40}$

$\frac{dq}{dp}=\frac{-47-3}{2*40}$

$\frac{dq}{dp}=\frac{-50}{80}$

$\frac{dq}{dp}=-0.625$

Thus, the rate of change of quantity with respect to price when p = $40 is -0.625 unit.

8 0

4 years ago

A study found that there is no direct relationship between the time that 8th-grade students spend brushing their teeth and their

Elza [17]

Answer:

Step-by-step explanation:

no correlation, because there's no direct relationship

7 0

3 years ago