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GuDViN [60]
2 years ago
10

HELP ME BRAINLIESTDoes this graph represent a proportional relationship? Explain.

Mathematics
2 answers:
alexira [117]2 years ago
8 0
I don't see any relationship...

A proportion can be written as an equation and equations are lines....
enyata [817]2 years ago
5 0

Answer:

Sample Response: This graph does not represent a proportional relationship because it is not a straight line, and the line does not pass through the origin.

Step-by-step explanation:

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When y=-2, what kind of line does it have horizontal or vertical
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Answer: Horizontal

Step-by-step explanation: The equation <em>y = -2</em> can be thought of as y = 0x - 2. So our line has a slope of 0 and a y-intercept of -2.

To graph it, we start with the y-intercept, down 2 units on the y-axis. Now, if the slope of a line is 0, then the line must be flat or horizontal.

So we just draw a horizontal line through the y-intercept of -2.

In fact, when the equation of any line reads y = a number, it's graph will always be a horizontal line. For example, y = 3, y = -10, y = -8 and so on.

Image provided below.

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3 years ago
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Which equation has no solution?
emmainna [20.7K]

Answer:

5 + 2(3 + 2x) = x + 3(x + 1)

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3 years ago
AM is a median in △ABC (M∈ BC ). A line drawn through point M intersects AB at its midpoint P. Find areas of △APC and △PMC, if A
Snowcat [4.5K]

Answer:

The area of APC is 70m². The area of triangle PMC is 35m².

Step-by-step explanation:

Let the area of triangle ABC be x.

It is given that AM is median, it means AM divides the area of triangle in two equal parts.

\text{Area of }\triangle ACM=\text{Area of }\triangle ABM=\frac{x}{2}    .....(1)

The point P is the midpoint of AB, therefore the area of APC and BPC are equal.

\text{Area of }\triangle APC=\text{Area of }\triangle BPC=\frac{x}{2}          ......(2)

The point P is midpoint of AB therefore the line PM divide the area of triangle ABM in two equal parts. The area of triangle APM and BPM are equal.

\text{Area of }\triangle APM=\text{Area of }\triangle BPM=\frac{x}{4}        .....(3)

The area of triangle APM is 35m².

\text{Area of }\triangle APM=\frac{x}{4}

35=\frac{x}{4}

x=140

Therefore the area of triangle ABC is 140m².

Using equation (2).

\text{Area of }\triangle APC=\frac{x}{2}

\text{Area of }\triangle APC=\frac{140}{2}

\text{Area of }\triangle APC=70

Therefore the area of triangle APC is 70m².

Using equation (3), we can say that the area of triangle BPM is 35m² and by using equation (2), we can say that the area of triangle BPC is 70m².

\triangle BPC=\triangle BPM+\triangle PMC

70=35+\triangle PMC

35=\triangle PMC

Therefore the area of triangle PMC is 35m².

8 0
3 years ago
Which of the following is the point-slope form of the line?
ryzh [129]

Answer:

A

Step-by-step explanation:

We can see that the slope is positive, which means that the x-term must be positive.

If you expand and simply both equations into the form y = mx + b, you will find that m is positive for A and negative for B, hence A is the correct answer.

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3 years ago
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