<h3>
Answer: Yes</h3>
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Explanation
The ratio 8:10 simplifies to 4:5 when you divide both parts by 2.
The ratio 16:20 simplifies to 4:5 when you divide both parts by 4
Therefore the two ratios 8:10 and 16:20 are both equal 4:5, so they are equal to one another.
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Put another way,
(8 large)/(10 small) = (16 large)/(20 small)
8/10 = 16/20
8*20 = 10*16 ... cross multiply
160 = 160
We get a true equation, so the first equation is true as well.
This shows the ratios are equivalent.
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Or you could have...
(8 large)/(16 large) = (10 small)/(20 small)
8/16 = 10/20
8*20 = 16*10
160 = 160
We get the same conclusion as before.
A = 2(9*11) + 1/2(8*11) + 1/2(8 * 9)
A = 198 + 44 + 36
A = 278
Answer
B. 278 in^2
<h2>
Answer with explanation:</h2>
Let
be the population mean.
By considering the given information , we have
Null hypothesis : 
Alternative hypothesis : 
Since alternative hypothesis is right-tailed , so the test is a right-tailed test.
Given : Sample size : n=16 , which is a small sample , so we use t-test.
Sample mean:
;
Standard deviation: 
Test statistic for population mean:

i.e. 
Using the standard normal distribution table of t , we have
Critical value for
: 
Since , the absolute value of t (2.333) is smaller than the critical value of t (2.602) , it means we do not have sufficient evidence to reject the null hypothesis.
Hence, we conclude that we do not have enough evidence to support the claim that answering questions while studying produce significantly higher exam scores.
Step-by-step explanation:
Given
A proportional relation is given between minutes spend in reading and no of pages
Suppose we choose the point
, It shows that 2 minutes is taken to read three pages.
Similarly, for point
, It shows four minutes is taken to read 6 pages.
In this way, 6 minutes is taken for 12 pages.