Use the information to write the dimensions of each rectangle in terms of w, the width of the 1st one.
1st rectangle;
l = 2w
w = 2
2nd rectangle:
w = w
l = 2w + 4
If the area of the 2nd rectangle is 70 square meters, you will use the area formula to write an equation that you will solve using the factoring.
A = lw
70 = w(2w + 4)
70 = 2w^2 + 4w
0 = 2w^2 + 4w -70
0 = 2 (w^2 +2w - 35)
0 = 2 (w + 7) (w - 5)
To get zero, the width would need to be -7 or 5. Because it is a distance, it has to be 5 meters.
The width of both rectangles is 5 meters.
So the “certain number” will be S.
Since 2width + 2length, the first part would be 2 times 2 which is 4
The length is S - 3
We then have to multiply this by 2
So it is 2(S-3) which is 2S-6
So the answer is 4+2S-6 which is 2S-2
Answer:
r=12
Step-by-step explanation:
Look, we can reverse the problem to get 23-11=r. This means that r=12.
y = 19
x = 4(19) + 21(19) = 76 + 399 = 475
3(475) × 7
1425 × 7
9975 <--- answer.
Hope this helped!
Nate
