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4 years ago

11

Find the length indicated

1 answer:

tankabanditka [31]4 years ago

8 0

you need subtract 19 and 7 and answer is 12 then you know that 15 is start of HK then add 15 and 12

I think the answer is 27

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Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

Read 2 more answers

Find the slope and y-intercept of y=8x-7

ICE Princess25 [194]

$\bf \begin{array}{|c|ll}\cline{1-1}\textit{slope-intercept form}\\\cline{1-1}\\y=\stackrel{slope}{m}x+\stackrel{y-intercept}{b}\\\\\cline{1-1}\end{array}~\hspace{2em} y=\stackrel{slope}{8}x\stackrel{y-intercept}{-7}~~\begin{cases}m=8\\y-intercept = (0, -7)\end{cases}$

5 0

3 years ago

410−x/7 +70=120. please answer fast i will give brainliest

galben [10]

410 - x/7 +70 = 120
410+70-120=x/7
360=x/7
X =2520

4 0

4 years ago

Read 2 more answers

A bag contains three yellow tickets numbered on to three. The bag also contains four green tickets numbered one to four. What is

Lelechka [254]

Answer:

6/7

Step-by-step explanation:

P(yellow or even) = 3/7 + 3/7 = 6/7

3 0

3 years ago

Determine algebraically wheather or not the function f(x)=-x^3 -2x^2 +5 is even or odd and justify your answer

IgorC [24]

Answer:

The function f(x) is neither even, nor odd function.

Step-by-step explanation:

<u>Definition: </u>A function is called an even function if for all x from its domain

$f(-x)=f(x)$

<u>Definition:</u> A function is called an odd function if for all x from its domain

$f(-x)=-f(x)$

You are given the function $f(x)=-x^3-2x^2+5.$

Substitute into the function expression -x instead of x.

$f(-x)=-(-x)^3-2(-x)^2+5\\ \\f(-x)=-(-x^3)-2x^2+5=x^3-2x^2+5\neq f(x)\\ \\-f(x)=-(-x^3-2x^2+5)=x^3+2x^2-5\\ \\f(-x)\neq -f(x)$

Hence, the function f(x) is neither even, nor odd function.

4 0

3 years ago