Can you tell me what 4% of ? is 56 days

What is pansexuality? Give in terms that an elementary schooler (fourth or fifth grader) would understand.

FinnZ [79.3K]

Answer:

See below.

Step-by-step explanation:

A pansexual is attracted to another regardless of their sex or gender identity.

8 0

3 years ago

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Meg is packing a shipping conditier.

allochka39001 [22]

Answer:

$Boxes= 198$

Step-by-step explanation:

<em>This question has uncleared details towards the end. However, one can deduce that we need to calculate the amount of box the available space can contain.</em>

<u>We have the following given parameters.</u>

<u>Shipping Container</u>

$Dimension: 2ft\ by\ 3ft\ by\ 33ft$

<u>The box</u>

$Dimension: 1ft\ by\ 1ft\ by\ 1ft$

First, we calculate the volume of the shipping container.

$V_A = 2ft * 3ft * 33ft$

$V_A = 198ft^3$

Next, we calculate the volume of the box.

$V_B = 1ft * 1ft * 1ft$

$V_B = 1ft^3$

The number of box is then calculated as:

$Boxes= \frac{V_A}{V_B}$

$Boxes= \frac{198ft^3}{1ft^3}$

$Boxes= \frac{198}{1}$

$Boxes= 198$

Hence:

<em>198 boxes will occupy the empty space</em>

4 0

3 years ago

A genetic experiment with peas resulted in one sample of offspring that consisted of 438 green peas and 173 yellow peas.

Andre45 [30]

Answer:

a

The 95% confidence interval is $0.2474 < p < 0.3188$

b

The result obtained does not contradict expectation

Step-by-step explanation:

From the question we are told that

The number of green peas is k = 438

The number of yellow peas is u = 173

Generally the sample size is mathematically represented as

$n = k + u$

=> $n = 438 + 173$

=> $n = 611$

Generally the sample proportion for yellow peas is

$\^ p = \frac{u}{n}$

=> $\^ p = \frac{173}{611 }$

=> $\^ p = 0.2831$

From the question we are told the confidence level is 95% , hence the level of significance is

$\alpha = (100 - 95 ) \%$

=> $\alpha = 0.05$

Generally from the normal distribution table the critical value of $\frac{\alpha }{2}$ is

$Z_{\frac{\alpha }{2} } = 1.96$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }$

=> $E = 1.96 * \sqrt{\frac{ 0.2831 (1- 0.2831)}{611} }$

=> $E = 0.0357$

Generally 95% confidence interval is mathematically represented as

$\^ p -E < p < \^ p +E$

=> $0.2831 -0.0357$

=> $0.2474 < p < 0.3188$

From the question we are told that it was expected that 25% of the offspring peas will be yellow

Now from the 95% confidence interval obtained we see that the expected sample proportion(25% ) falls within it so it means that the result obtained does not contradict expectation

7 0

2 years ago

PLEASE ANSWER ASAP!!

Rufina [12.5K]

Answer:

The instantaneous rate of increase of f(x) at $x_{0} = 3$ is 3.
One possible equation of this line is y = 3x - 16.
The line is tangent to the graph of y = f(x). The slope of the line is the same as the instantaneous rate of increase of f(x) at $x_{0} = 3$ .

Step-by-step explanation:

$\begin{aligned}&\lim_{h\to 0}{\frac{f(3+h)-f(h)}{h}}\\ =&\lim_{h\to 0}\frac{1}{h} \cdot [(3^{3} + 3 \times 3^{2}h +3\times 3h^{2} + h^{3})- 4(3^{2} + 2\times 3h + h^{2}) + 2 \\[-1em] &\phantom{\lim_{h\to 0}\frac{1}{h}\cdot []} -(3^{3} -4\times 3^{2} + 2)]\\ = &\lim_{h \to 0}\frac{h^{3} + 5h^{2} +3h}{h}\\=& \lim_{h \to 0}{h^{2}} + \lim_{h \to 0}{5h} + \lim_{h\to 0}{3}\\ =& 3\end{aligned}$ .

$f(3) = 3^{3} - 4\times 3^{2} + 2 =-7$ .

In other words, the graph of y = f(x) passes through the point (3, -7) where $x = 3$ .

The point-slope form of a line in a cartesian plane is:

$y - y_0 = m (x - x_0)$ .

For this line,

$(3, -7)$ is the point on the line, while

$3$ is the slope of the line.

The equation of this line will thus be

$y - (-7) = 3(x - 3)$ .

That's equivalent to

$y = 3x - 16$ .

Refer to the diagram attached. The line touches the graph of y = f(x) at x = 3 without crossing it. The line here is thus a tangent to the graph of y = f(x) at x = 3. The slope of the line represents the instantaneous rate of increase of f(x) at $x_{0} = 3$ .

4 0

3 years ago

The coordinates of the vertices of quadrilateral ABCD are A(-5, 1), B(-2,5), C(5, 3),

sladkih [1.3K]

Step-by-step explanation:

To calculate a slope, we need to apply: $m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Applying formula to each slope:

$m_{AB}=\frac{5-1}{-2-(-5)} = \frac{4}{3} \\m_{BC}=\frac{3-5}{5-(-2)} =\frac{-2}{7}\\m_{CD}=\frac{-1-3}{2-5}=\frac{-4}{-3} =\frac{4}{3}$

So, as you can see, there are equal pair of slopes, meaning that they are parallels, which<em> demonstrate that it's actually a quadrilateral figure.</em>

6 0

3 years ago

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