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marta [7]
3 years ago
12

Find the values if x and y

Mathematics
1 answer:
SOVA2 [1]3 years ago
5 0

Note that: (10x - 61) & (x + 10) are supplementary angles, and (10x-61) & (18y + 5) are vertical angles

10x - 61 + x + 10 = 180

Simplify

11x - 51 = 180

Isolate the x

11x - 51 (+51) = 180 (+51)

11x = 231

Divide 11 from both sides

11x/11 = 231/11

Divide

x = 21

180 = 18y + 5 + x + 10

180 = 18y + 5 + (21) + 10

Simplify

180 = 18y + 36

Subtract 36 from both sides

180 (-36) = 18y + 36 (-36)

144 = 18y

Divide 18 from both sides

144/18 = 18y/18

y = 144/18

y = 8

x = 21, y = 8 are your answers

hope this helps


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Why can we write zeros after a number when we multiply by 10, 100, or 1000.
allochka39001 [22]

Answer:

IT shows that we are increasing the value of the number. The more zeros at the end of a number that you multiply by, the bigger the number will be.

Examples: 76x100=7600

                  100x100=10,000

However many zeros are behind the number is what you add to the product.

Step-by-step explanation:

3 0
3 years ago
Solve the system using elimination. 3x – y = 28 3x + y = 14
Vikki [24]

Answer:

x= 7, y= -7         or          (7, -7)

Step-by-step explanation:

3x-y=28

3x+y=14

because the y is opposite of each other in both equations you can cancel them out

3x=28

3x=14

next you add 3x to 3x, then 28 to 14 and get...

6x=42

next divide both sides by 6 and you get your answer for x...

x=7

now you must solve for y and you do this by substituting what you found for x in one equation it doesn't matter which because you'll get the same answer but you can check for both to make sure...

3(7)+y=14

21+y=14

y=-21+14

y=-7

4 0
3 years ago
Read 2 more answers
Solve the equation 23 = h - 52 for h
Semenov [28]
23 = h -52
23+52 = h -52 +52
75 = h
7 0
3 years ago
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GRAVITATION The height h(t) in feet of an object t seconds after it is propelled straight up from the ground with an initial vel
zhuklara [117]
<h3>Option B</h3><h3>At 2 second and 1.75 second, the object be at a height of 56 feet</h3>

<em><u>Solution:</u></em>

Given that,

<em><u>The height h(t) in feet of an object t seconds after it is propelled straight up from the ground with an initial velocity of 60 feet per second is modeled by the equation:</u></em>

h(t) = -16t^2 + 60t

<em><u>At what times will the object be at a height of 56 feet</u></em>

<em><u>Substitute h = 56</u></em>

56 = -16t^2 + 60t\\\\16t^2 - 60t + 56 = 0\\\\Divide\ the\ equation\ by\ 4\\\\4t^2 - 15t + 14=0

Solve the above equation by quadratic formula

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=4,\:b=-15,\:c=14\\\\x =\frac{-\left(-15\right)\pm \sqrt{\left(-15\right)^2-4\cdot \:4\cdot \:14}}{2\cdot \:4}\\\\Simplify\\\\x = \frac{15 \pm \sqrt{1}}{8}\\\\x = \frac{15 \pm 1}{8}\\\\We\ have\ two\ solutions\\\\x = \frac{15+1}{8} \text{ and } x = \frac{15-1}{8}\\\\x = 2 \text{ and } 1.75

Thus, at 2 second and 1.75 second, the object be at a height of 56 feet

5 0
4 years ago
Solve for the value of r.<br> r =
Kay [80]

Answer:

r=8

Step-by-step explanation:

45=6r-3

48=6r

r=8

3 0
3 years ago
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