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3 years ago

Find the values if x and y

Mathematics

1 answer:

SOVA2 [1]3 years ago

5 0

Note that: (10x - 61) & (x + 10) are supplementary angles, and (10x-61) & (18y + 5) are vertical angles

10x - 61 + x + 10 = 180

Simplify

11x - 51 = 180

Isolate the x

11x - 51 (+51) = 180 (+51)

11x = 231

Divide 11 from both sides

11x/11 = 231/11

Divide

x = 21

180 = 18y + 5 + x + 10

180 = 18y + 5 + (21) + 10

Simplify

180 = 18y + 36

Subtract 36 from both sides

180 (-36) = 18y + 36 (-36)

144 = 18y

Divide 18 from both sides

144/18 = 18y/18

y = 144/18

y = 8

x = 21, y = 8 are your answers

hope this helps

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$\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]+\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]=\left[\begin{array}{cc}4&5\\13&-13\end{array}\right]$

Step-by-step explanation:

If you have two matrices:

$A=\left[\begin{array}{cc}a&b\\c&d\end{array}\right]\\and\\B=\left[\begin{array}{cc}e&f\\g&h\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}a+e&b+f\\c+g&d+h\end{array}\right]$

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$A=\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]\\and\\B=\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]$

And we need to express as a single matrix:

$A+B=\left[\begin{array}{cc}6&-3\\10&-1\end{array}\right]+\left[\begin{array}{cc}-2&8\\3&-12\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}6+(-2)&-3+8\\10+3&-1+(-12)\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}6-2&5\\13&-1-12\end{array}\right]\\\\\\A+B=\left[\begin{array}{cc}4&5\\13&-13\end{array}\right]$

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