The minimum distance will be along a perpendicular line to the river that passes through the point (7,5)
4x+3y=12
3y=-4x+12
y=-4x/3+12/3
So a line perpendicular to the bank will be:
y=3x/4+b, and we need it to pass through (7,5) so
5=3(7)/4+b
5=21/4+b
20/4-21/4=b
-1/4=b so the perpendicular line is:
y=3x/4-1/4
So now we want to know the point where this perpendicular line meets with the river bank. When it does y=y so we can say:
(3x-1)/4=(-4x+12)/3 cross multiply
3(3x-1)=4(-4x+12)
9x-3=-16x+48
25x=51
x=51/25
x=2.04
y=(3x-1)/4
y=(3*2.04-1)/4
y=1.28
So now that we know the point on the river that is closest to Avery we can calculate his distance from that point...
d^2=(x2-x1)^2+(y2-y1)^2
d^2=(7-2.04)^2+(5-1.28)^2
d^2=38.44
d=√38.44
d=6.2 units
Since he can run at 10 uph...
t=d/v
t=6.2/10
t=0.62 hours (37 min 12 sec)
So it will take him 0.62 hours or 37 minutes and 12 seconds for him to reach the river.
Answer:
4x-12 or 4(x-3)
Step-by-step explanation:
9x+9+2x-7(3+x)
9x+2x+9-21-7x
11x-12-7x
11x-7x-12
4x-12
Answer:
The 21st term is 137.
Step-by-step explanation:
Arithmetic progression:
In an arithmetic progression the difference between consecutive terms is always the same, and its called common difference.
The nth term is given by:
In which 
is the first term and d is the common difference.
The first two terms are -3, 4.
This means that 
So
The 21st term is
The 21st term is 137.
Answer:
The volume of the community swimming pool is 4 times greaters than the volume of the wading pool.
Step-by-step explanation:
By definition of rectangular prism, we get the respective formulas for the volumes of the community swimming pool and the wadling pool, respectively:
Community swimming pool
Wading pool
Where:
l – Length of the swimming pool, measured in feet.
h – Depth of the swimming pool, measured in feet.
w – Width of the swimming pool, measured in feet.
– Volume of the community swimming pool, measured in cubic feet.
– Volume of the wading swimming pool, measured in cubic feet.
The ratio of the volume of the community swimming pool to the volume of the wadling pool is:
The volume of the community swimming pool is 4 times greaters than the volume of the wading pool.
y = -0.60x - 4
because the slope stays the same because it is parallel and the y intercept for the new equation ends up being -4
