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Vladimir79 [104]
2 years ago
8

plzzz finish 4, 5, 6, 9, 10, 11, 12, 14, and 15 you dont have to answer all but atleast anwer like 2 or 3 \( i scratched out the

answered questions the ones I answered)

Mathematics
1 answer:
nika2105 [10]2 years ago
8 0

Answer:

4. -4

5. -2

6. -3

Step-by-step explanation:

4. -12 = 5r + 8

Subtract 8 from both sides;

-20 = 5r

Divide both sides by 5;

-4 = r OR r = -4

5. -6p - 3 = 9

Add 3 to both sides;

-6p = 12

Divide both sides by -6

p = -2

6. -14 = 4x - 2

Add 2 to both sides;

-12 = 4x

Divide both sides by 4;

-3 = x OR x = -3

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At 5 seconds, an object's velocity is 9 meters per second. At 8 seconds, the object's velocity is 25 meters per second. Assuming
RideAnS [48]

Acceleration  =  (change in speed) / (time for the change) .

Change in speed = (25 m/s - 9 m/s) =  16 m/s

Time for the change = (8 sec  -  5 sec)  =  3 seconds

Acceleration  =  (change in speed) / (time for the change)

                       =                 (16 m/s)  /  (3 sec) 

                       =                          (5 and 1/3)  m/s²  .

(rounded to the nearest hundredth ...  5.33 m/s² . )
7 0
3 years ago
A triangle has three sides 35cm 54 cm and 61 cm find its area Also find the smallest of its altitude ​
I am Lyosha [343]

Answer:

Area of given triangle is 939.15cm² and smallest altitude is 30.8cm

<h3>Solution:</h3>

We are given three sides of a triangle, Let the sides be :

  • ( a ) = 35 cm

  • ( b ) = 54 cm

  • ( c ) = 61 cm

We can find the area of the triangle with its three sides using Heron's Formula

  • <u>Heron's </u><u>Formula</u>

Heron's formula was founded by hero of Alexandria, for finding the area of triangle in terms of the length of its sides. Heron's formula can be written as:

\sf{   \pmb { \longrightarrow \:  \sqrt{s(s - a)(s - b)(s - c)} }}

where ( s ) :

\sf \longrightarrow s = \dfrac{a + b + c}{2}

Therefore, for the given triangle first we will calculate ( s )

\begin {aligned}\quad & \quad \longmapsto  \sf  s =  \dfrac{a + b + c}{2}  \\  & \quad \longmapsto  \sf s =  \dfrac{35 + 54 + 61}{2}  \\ & \quad \longmapsto  \sf s =  \dfrac{150}{2}  \\ & \quad \longmapsto  \sf s  = 75cm \end{aligned}

Now, Area of triangle will be:

\begin{aligned}&:\implies \sf\quad \sf \:  A = \sqrt{s(s - a)(s - b)(s - c)} \\ &:\implies \sf\quad \sf \:  A = \sqrt{75(75 - 35)(75 - 54)(75 - 61)}   \\&:\implies \sf\quad \sf \:  A = \sqrt{75 \times 40 \times 21 \times 14}  \\ &:\implies \sf\quad \sf \:  A = \sqrt{5 \times 5 \times 3 \times 3 \times 2 \times 2 \times 7 \times 7 \times 2 \times 2 \times 5}  \\ &:\implies \sf\quad \sf \:  A =5 \times 3 \times 2 \times 7 \times 2 \sqrt{5}  \\ &:\implies \sf\quad \sf \:  A =420 \times 2.23 \\ &:\implies \sf\quad \sf \boxed{ \pmb{ \sf   A =939.15 {cm}^{2} }} \end{aligned}

Also, we have to find the smallest altitude, and the smallest altitude will be on the longest side. So,

\begin{aligned}&:\implies \sf\quad \sf \:  Area =939.15 \\ &:\implies \sf\quad \sf \:   \dfrac{1}{2}  \times b \times h =939.15 \\ &:\implies \sf\quad \sf \:   \dfrac{1}{2} \times 61 \times h  = 939.15 \\&:\implies \sf\quad \sf \:  h =939.15 \times  \dfrac{2}{61}   \\&:\implies \sf\quad \sf \:  h = \dfrac{1818.3}{61}  \\ &:\implies \sf\quad  \boxed{ \pmb{\sf \:  h =30.79 \: (approx)}} \end{aligned}

3 0
2 years ago
Read 2 more answers
Someone help me with this question please I don’t know
ra1l [238]

The magic of the internet will help!

6 0
2 years ago
C = k - 273.15 (a) Write two other related equations . (b) If the temperature is 23 in degrees Celsius , what is the temperature
Alona [7]

Answer:

(a) k = C + 273.15, F = 1.8(k - 273.15) + 32

(b) k = 296.15

(c) 25 celcius is greater than 300 kelvis.

Step-by-step explanation:

(a) one equation would be to solve for k instead of c, and another related equation could be from kelvin to Farenheit.

C = k - 273.15

C + 273.15 = k

k = C + 273.15

F = 1.8(k - 273.15) + 32

(b) for this one you have to substitute in the previous equation and solve for k.

23 = k - 273.15

k = 23 + 273.15

k = 296.15

(c) you have to convert either kelvins to celcius or celcius to kelvins.

C = k - 273.15

C = 300 - 273.15

C = 26.85

So 25 celcius is greater than 300 kelvis.

5 0
2 years ago
Assume that all angles are right angles. 60in,20in,20in,10in and 20 in
Fofino [41]
The answer is 1000 square inches.
8 0
2 years ago
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