Mass = volume × density;
mass = 2.5g/mL x 15mL;
mass = 37.5g;
Answer:
As noted in the comments, we need to find out which of those functions return a value of 14 when x is equal to 3.
No one of these functions gives ups a value of 3, but if we use them in combination, we can say that f(g(3)) gives us an end value of 14.
It may be that other combinations will give you the same result, but that is the most obvious one.
Step-by-step explanation:
Let's test each one:
None of these give a return value of 14 when x equals 3. Perhaps though, we can combine them to get the desired result?
Let's try f(g(3)):
Answer: -2
Step-by-step explanation: As our first step, we simplify inside the absolute value. 7 - 9 is -2 so we have -|-2|.
A common mistake at this point in the problem is to change the minus a negative to plus a positive but don't fall into this trap.
We must ignore the negative outside the absolute value until our very last step in this problem.
So we take the absolute value of -2 which is 2 and we have -(2) or -2.
Notice that I used parentheses around the 2 as it comes out of the absolute value.
Answer: 1
-----------------------------------------------------
Explanation:
Replace every copy of x with -1. Then use PEMDAS to simplify
F(x) = -x^3 - x^2 + 1
F(-1) = -(-1)^3 - (-1)^2 + 1 ... every x has been replaced with -1
F(-1) = -(-1) - 1 + 1
F(-1) = 1 - 1 + 1
F(-1) = 0 + 1
F(-1) = 1