Yes it is :)
If there is an outlier on the lower end of the graph the mean will go down. If there is an outlier at the higher end of the graph the mean will go up.
Complete Question
A population has a mean of 25, a median of 24, and a mode of 26. The standard deviation is 5. The value of the 16th percentile is _______. The range for the middle 3 standard deviation is _______.
Answer:
The value of the 16th percentile is 
The range for the middle 3 standard deviation is 
Step-by-step explanation:
From the question we are told that
The mean is 
The median is 
The mode is 
The standard deviation is 
Generally the 16th percentile is mathematically represented as
![P(x)= P(\frac{X - \mu }{ \sigma } \le \frac{x- 25 }{5} ) = 0.16[/teGenerally [tex]\frac{X - \mu}{\sigma } = Z(The \ standardized \ value \ of \ X )](https://tex.z-dn.net/?f=P%28x%29%3D%20P%28%5Cfrac%7BX%20%20-%20%20%5Cmu%20%7D%7B%20%5Csigma%20%7D%20%20%20%5Cle%20%5Cfrac%7Bx-%2025%20%7D%7B5%7D%20%29%20%3D%200.16%5B%2Fte%3C%2Fp%3E%3Cp%3EGenerally%20%20%5Btex%5D%5Cfrac%7BX%20-%20%20%5Cmu%7D%7B%5Csigma%20%7D%20%20%3D%20%20Z%28The%20%20%5C%20%20standardized%20%5C%20%20value%20%5C%20of%20%20%5C%20X%20%20%29)
So

Now from the normal distribution table the z-score of 0.16 is
z = -1

=> 
=> 
=> 
=> 
The range for the middle 3 standard deviation is mathematically represented



Step-by-step explanation:
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Answer:
50°
Step-by-step explanation:
An inscribed angle is half the measure of its intercepted arc. Here, arc AC is ∠B's intercepting arc. Arc AC is 100°, and 100/2 = 50, so ∠B is 50°.