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3 years ago

I really need help >_< please and thank you

Mathematics

1 answer:

SashulF [63]3 years ago

8 0

So for each of the graphs, you basically just have to fill out slope form, which is y=my+b. And to make this equation, you need to find each variable.

First, find the slope. To calculate slope, count the rise (how many units up or down) the line goes from any point to the next immediate point, then the run (how many units left or right.) This should leave you with a fraction, rise/run. For example, on number 3, from labeled points (-5, -4) to (5,2) (double check cause it’s hard to see on my phone, but i think those are the points on 1??) it rises 6 units (-4 to 2) and runs 10 units (-5 to 5). This gives you your rise/run fraction, which is 6/10, simplified to 3/5.

So the slope fills out the m part of the equation. For 3, we found that slope is 3/5, and that fits into the m variable of the slope equation.

This makes it y=3/5x+b.

The last (and considerably less confusing) step is to find b. b is the y-intercept, which is just the point in the graph where the line crosses the y-axis and x=0. On 3, this would be (0,-1) or just -1.

So fill -1 into the b slot of the equation, and you get y=3/5x-1. And thats it!!

Let me know if you still need help on any of the other problems, but I hoped this helped to clear it up!! :)

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An equivalent expression with a rational denominator is...

Whitepunk [10]

Given the expression,

$(8x-56x^2)/(\sqrt{14x-2})$

We will have to rationalize the denominator first. To rationalize the denominator we have to multiply the numerator and denominator both by the square root part of the denominator.

$[(8x-56x^2)(\sqrt{14x-2})]/[(\sqrt{14x-2})(\sqrt{14x-2})]$

If we have $(\sqrt{a})(\sqrt{a})$ , we will get $\sqrt{a^2}$ by multiplying them. And $\sqrt{a^2} = a$ .

So here in the problem, we will get,

$[(8x-56x^2)(\sqrt{14x-2})]/(14x-2)$

Now in the numerator we have $(8x-56x^2)$ . We can check 8x is common there. we will take out -8x from it, we will get,

$-8x(-1+7x)$

$-8x(7x-1)$

And in the denominator we have $14x-2$ . We can check 2 is common there. If we take out 2 from it we will get,

$2(7x-1)$

So we can write the expression as

$[(-8x)(7x-1)(\sqrt{14x-2})]/[2(7x-1)]$

$(7x-1)$ is common to the numerator and denominator both, if we cancel it we will get,

$(-8x)(\sqrt{14x-2})/2$

We can divide -8 by the denominator, as -8 os divisible by 2. By dividing them we will get,

$(-4x)(\sqrt{14x-2})$

$(-4x)(14x-2)^(1/2)$

So we have got the required answer here.

The correct option is the last one.

4 0

3 years ago

Lesson 16

Goshia [24]

Answer:

546 ft³

Step-by-step explanation:

In the figure attached, the top view of the pool is shown. It can be decomposed into a trapezoid which height is 12 ft and which bases are 9 ft and 11 ft; and a rectangle which height is 1.5 ft and and it base is 11 ft.

Area of the trapezoid: (9 + 11)/2 * 12 = 120 ft²

Area of the rectangle: 1.5*11 = 16.5 ft²

Total area: 120 + 16.5 = 136.5 ft²

Volume of the pool: Total area * deep = 136.5 * 4 = 546 ft³