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iris [78.8K]
3 years ago
14

The length of a track around a field is 1/4 miles. You run 3 1/2 times

Mathematics
1 answer:
irina [24]3 years ago
4 0

Answer: 7/8 of a mile

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Please help ASAP Select two points to define a line where the polygon will break
andriy [413]

Answer:

2 one and the 4 one

Step-by-step explanation:

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Simplify. -15-(-3)+6 
miv72 [106K]
-15 - (-3) + 6

-15 - (-3) = -15 + 3 = 3 - 15 = - 12

-12 + 6 = 6 - 12 = -6

Your answer is -6
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3 years ago
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The mean length of 4 childrens' big finger is 14cm. The mean length of 9 adults' big finger is 16.1cm. What is the mean length (
Mamont248 [21]

Answer:

The mean length of the 13 people's big finger is 15.45 cm

Step-by-step explanation:

Given;

mean length of 4 childrens' big finger, x' = 14cm

mean length of 9 adults' big finger is 16.1cm, x'' = 16.1cm

Let the total length of the 4 childrens' big finger = t

x' = \frac{t}{n} \\\\x' = \frac{t}{4}\\\\t = 4x'\\\\t = 4 *14\\\\t = 56 \ cm

Let the total length of the 9 adults' big finger = T

x'' = \frac{T}{N} \\\\x'' = \frac{T}{9}\\\\T = 9x''\\\\T = 9*16.1\\\\T = 144.9 \ cm

The total length of the 13 people's big finger = t + T

                                                                           = 56 + 144.9

                                                                            =200.9 cm

The mean length of these 13 people's big finger;

x''' = (200.9) / 13

x''' = 15.4539 cm

x''' = 15.45 cm (2 DP)

Therefore, the mean length of the 13 people's big finger is 15.45 cm

3 0
3 years ago
Restless Leg Syndrome and Fibromyalgia
mixas84 [53]

Answer:

The probability that a person with restless leg syndrome has fibromyalgia is 0.1833.

Step-by-step explanation:

Denote the events as follows:

<em>F</em> = a person with fibromyalgia

<em>R</em> = a person having restless leg syndrome

The information provided is as follows:

P (R | F) = 0.33

P (R | F') = 0.03

P (F) = 0.02

Consider the tree diagram attached below.

Compute the probability that a person with restless leg syndrome has fibromyalgia as follows:

P(F|R)=\frac{P(R|F)P(F)}{P(R|F)P(F)+P(R|F')P(F')}\\\\=\frac{(0.33\times 0.02)}{(0.33\times 0.02)+(0.03\times 0.98)}\\\\=0.183333\\\\\approx 0.1833

Thus, the probability that a person with restless leg syndrome has fibromyalgia is 0.1833.

6 0
3 years ago
William gave 4 football cards to each
andreev551 [17]

Answer:

Cannot be determined

Step-by-step explanation:

There is not enough information to solve this question. You would need to know how many friends he has in order to solve this.

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