F(5)-f (1)/5-1 gives avg over the interval
(14-6)÷(6-2)___ 4×(10-8)-2×2
8 4 2
8÷4 __ 4×2-2×2
0
2 < 8
Solve simultaneously:
<span>15x-8y=52 and
6x+14y=38
</span>
Let's solve this system thru elimination by addition/subtraction:
Let's get rid of the x terms.
To do this, mult. the first eqn. by -6 and the second by 15. (This is not the only way in which we can do this!!) We get
-90x + 48y = -312
90x +210y = 570
--------------------------
Add all 3 columns together. We end up with:
258y = 258, so y = 1. You can find x by subst. 1 for y in either of the given equations.
If you'd like more help, please be specific about what you want.
Answer:
The point must be between 5 and 6, accurately in 5,4
Step-by-step explanation:
SQT[29] = 5,38
Best regards
Solve whats in the parentheses first
5k+25+4<21+6k
5k+29<21+6k
plug in a number in k for both sides
5(1)+29<21+6(1)
5+29<21+6
34<27
5(2)+29<21+6(2)
10+29<21+12
39<33
so 5(k+5)+4 is greater than 21+6k
