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Allushta [10]
1 year ago
11

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Mathematics
1 answer:
Archy [21]1 year ago
6 0
Each quarter of a set of data is denoted by a quartile:

The 25th percentile makes up the first quartile Q1.
The 50th percentile represents the second quartile Q2.
The 75th percentile is the third quartile, or Q3.
Finding the second quartile, Q2, is simple. It divides an ordered data set into upper and lower half and is the median of any data set.

The median of the bottom half, excluding the value of Q2, makes up the first quartile, or Q1. The median of the upper half, excluding the value of Q2, makes up the third quartile, or Q3.

Sort the values in your data set from lowest to highest.
the median, please. Q2 stands for the second quartile.
Divide the ordered data collection in half at Q2.
The median of the lower half of the data makes up the lower quartile Q1.
The median of the data's upper half represents the upper quartile Q3.
When determining the first and third quartiles, omit the median if the size of the data set is unusual.
The median, if the size of the data collection is even, is the average of the middle two values. Add the two figures together, then divide by two. The value of the median, which divides the data set into lower and higher half, is

How to Find Interquartile Range
The interquartile range IQR is the range in values from the first quartile Q1 to the third quartile Q3. Find the IQR by subtracting Q1 from Q3.

IQR = Q3 - Q1

How to Find the Minimum

The minimum is the smallest value in a sample data set. Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the minimum is the smallest value x1. The formula for minimum is:

Min=1=min()=1

How to Find the Maximum

The maximum is the largest value in a sample data set.

Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the maximum is the largest value xn. The formula for maximum is:

Max==max()=1

How to Find the Range of a Set of Data

The range of a data set is the difference between the minimum and maximum. To find the range, calculate xn minus x1.

=−1

So to Answer your question


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You are in a hot air balloon looking down at two ponds. Pond A which is in front of your balloon, is at an angle of depression t
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a. See attachment for the labelled diagram

b. Using the sine ratio, distance from the hot air to pond A is 5,038.9 m, while distance from the hot air to pond B is 6,287.1 m.

c. Distance between the two ponds is 1,263.5 m.

<h3>What is the Sine and Tangent Ratios?</h3>

Sine ratio, is: sin ∅ = opposite side/hypotenuse length

Tangent ratio is: tan ∅ = opposite side/adjacent length.

a. The diagram with the appropriate labels is shown in the image attached below.

b. Use the sine ratio to find the distance from the hot air to pond A (CA) and to pond B (CB):

CA = hypotenuse

∅ = 10°

Opposite = 875 m

sin 10 = 875/CA

CA = 875/sin 10

CA ≈ 5,038.9 m (distance from the hot air to pond A)

CB = hypotenuse

∅ = 8°

Opposite = 875 m

sin 8 = 875/CB

CB = 875/sin 8

CB ≈ 6,287.1 m (distance from the hot air to pond B)

c. Distance between the two ponds, BA = BD + DA.

Apply the tangent ratio to find BD and DA

tan 8 = 875/BD

BD = 875/tan 8

BD = 6,225.9 m

tan 10 = 875/DA

DA = 875/tan 10

DA = 4,962.4 m

Distance between the two ponds = 6,225.9 - 4,962.4 = 1,263.5 m.

Learn more about the sine and tangent ratios on:

brainly.com/question/24137232

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8 0
2 years ago
The figure below shows a shaded region and a non-shaded region. Angles in the figure that appear to be right angles are right an
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Answer:

Step-by-step explanatioihhin:

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Students are voting on a color T-shirt to wear on there field trip. There are 160 students-65 boys and 95 girls-going on the fie
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3 years ago
A large two topping from Tonys pizzaeria has 8 slices and costs $16.00 vivian wants to know the cost per slice
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Answer:

divide

Step-by-step explanation:

you divide and then use that 2 to 1 ratio

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3 years ago
Robert owns a doggy hotel. This is like a kennel but much fancier. Last friday the 14th he had 35 dogs that ate 3/8 of a pound o
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Answer:

the 7th

0.007805 or  59 / 756

Step-by-step explanation:

To determine the Friday that he needed more pounds, determine the number of pounds he needed per dog for each Friday.

to do this, divide the total pounds by the number of dogs

on the 14th

3/8 ÷ 35 =

3/8 x 1/35 = 3/280

on the 7th

1/2 ÷ 27 =

1/2 x 1/27 = 1/54

to determine which fraction is larger multiply each by 100 to determine its percent

3/280 x 100 = 1.071

1/54 x 100 = 1.852

1/54 is larger. Thus, more pounds was needed on Friday the 7th

the difference between these fractions should be determined  

\frac{1}{54} - \frac{3}{280}

\frac{280 - 162}{1512} = \frac{118}{1512} = 59 / 756

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