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Alisiya [41]
3 years ago
15

Which formula represents the compound commonly known as phosphine PH PH2 PH3 PH4

Chemistry
2 answers:
deff fn [24]3 years ago
8 0
"PH3" is the one formula among the following choices given in the question that <span>represents the compound commonly known as phosphine. The correct option among all the options that are given in the question is the third option or the penultimate option. I hope that this is the answer that has come to your help.</span>
AveGali [126]3 years ago
4 0
The answer is C). PH3
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Giving brainliest to whoever answers, correctly.
velikii [3]
The answer is c. Your welcome
8 0
3 years ago
A chemist measures the solubility of lead(ii) bromide in water to be 2. 96 g/l. calculate the ksp value for the solid. the ksp v
Julli [10]

The solubility product, ksp of PbBr₂ is 2.102 × 10⁻⁶

<h3>What is solubility?</h3>

The solubility of a solute is defined as the maximum amount of that solute that can be dissolved in a known quantity of solvent at a given temperature.

<h3>What is a solubility product? </h3>

Some salts are sparingly soluble in a solvent. For them, we calculate the solubility product.

It is an equilibrium constant that defines the relationship between a solid and its respective ions in an aqueous solution in equilibrium.

The greater the solubility product, the greater the solubility and vice versa.

Here, the solubility of PbBr₂ = 2.96 g/l

Molar solubility of  PbBr₂ = \frac{2.96}{molar mass of PbBr_2} = 2.96/367 = 8.07 × 10⁻³

At equilibrium,

PbBr_2\rightarrow Pb^{2+} + 2Br^-

1 mole of PbBr2 dissociates into 1 mole of Pb²⁺ ions and 2 moles of Br⁻

Let the molar concentration of Pb²⁺ be x, then the molar concentration of Br⁻ is 2x

Ksp = x.(2x)²

       = 4x³

Substitute, x = 8.07 × 10⁻³

Ksp = 4 (8.07 × 10⁻³)³

      = 2.102 × 10⁻⁶

Thus, The ksp of PbBr₂ is 2.102 × 10⁻⁶

Learn more about solubility product:

brainly.com/question/1419865

#SPJ4

5 0
2 years ago
Write the half-reactions as they occur at each electrode and the net cell reaction for this electrochemical cell containing indi
AlexFokin [52]

Explanation:

The given cell reaction is as follows.

       In(s)| In^{3+}(aq) || Cd^{2+}(aq) | Cd(s)

Hence, reactions taking place at the cathode and anode are as follows.

At anode ; Oxidation-half reaction : In(s) \rightarrow In^{3+}(aq) + 3e^{-} ...... (1)

At cathode; Reduction-half reaction : Cd^{2+}(aq) + 2e^{-} \rightarrow Cd(s) ....... (2)

Hence, balance the half reactions by multiplying equation (1) by 2 and equation (2) by 3.

Therefore, net cell reaction is as follows.

      2In(s) \rightarrow 2In^{3+}(aq) + 6e^{-}

      3Cd^{2+}(aq) + 6e^{-} \rightarrow 3Cd(s)

Net reaction: 2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)

Thus, we can conclude that the overall cell reaction is as follows.

        2In(s) + 3Cd^{2+}(aq) \rightarrow 2In^{3+}(aq) + 3Cd(s)

4 0
3 years ago
What is the primary meaning when we say that something burns?
enyata [817]
When something burns it usually means something is being damaged or being changed such as colour, smell, or shape.
5 0
4 years ago
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Read the following statement:
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The last one should be right
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