Answer:
36 mL of water can be displace by the 408 g lead
Explanation:
Given data:
Mass of lead = 408 g
Volume of water displaced by lead = ?
Solution:
The volume of water displace by the lead would be equal to the given volume of lead.
So we will calculate the volume from given mass of lead from density formula.
Density:
Density is equal to the mass of substance divided by its volume.
Units:
SI unit of density is Kg/m3.
Other units are given below,
g/cm3, g/mL , kg/L
Formula:
D=m/v
D= density
m=mass
V=volume
Density of lead is 11.36 g/cm³.
d = m/v
11.36 g/cm³ = 408 g/ v
v = 408 g/ 11.36 g/cm³
v =36 cm³
1 cm³ = 1 mL
volume = 36 mL
36 mL of water can be displace by the 408 g lead.
Potassium nitrate does not have a net ionic equation. It is because potassium nitrate is not soluble and does not produce precipitates. The net ionic reaction is going to be Zn2+ + S2- -> ZnS(s). Zinc sulfide precipitates in the net ionic reaction.
Answer:
Element Z
Explanation:
I hope this is correct and helps you!
A. True
They are formed behind an obstacle when the wind blows the sand up to it.
