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mariarad [96]
3 years ago
5

Propane gas (C3H8) burns completely in the presence of oxygen gas (O2) to yield carbon dioxide gas (CO2) and water vapor (H2O).

Chemistry
1 answer:
Sindrei [870]3 years ago
7 0
Oxen beacon is great for your self halllway
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Help me please I need help
yanalaym [24]
37. Is D
38. Is C
39. Is A
40. Is A
41. Is D I think!
I'm 100% positive about 37-40 but I'm 50% sure on question number 41.
I hope this helped!
4 0
3 years ago
A Pitot-static probe is used to measure the speed of an aircraft flying at 3000 m. If the differential pressure reading is 3100
inessss [21]

Answer:

82.59 m/s or 297.324 km/h

Explanation:

From the question,

Applying

V = √[2(P'/ρ)].................. Equation 1 ( From

Where V = Speed of the aircraft, Differential Pressure of the air craft, ρ = Density of air at an altitude of 3000 m.

Given: P' = 3100 N/m², ρ = 0.909 kg/m³

Substitute into equation 1

V = √[2(3100/0.909)]

V = √(2×3410.34)

V = √(6820.68)

V = 82.59 m/s

V = 297.324 km/h

Hence the speed of the aircraft is  82.59 m/s or 297.324 km/h

3 0
3 years ago
The equilibrium system described by this equation has reactant molecule(s) and product gas molecule(s).
Evgesh-ka [11]

For N2(g)+3h2(g) ←→ ​​​​​​​2nh3(g) The equilibrium system described by this equation has= 3  reactant molecule(s) and= 2  product gas molecule(s).

5 0
3 years ago
Read 2 more answers
Which of the following statements is not accurate? A. At constant temperature, halving the number of gas particles in a given sp
vlabodo [156]
I suggest you to go with C !! it is absolutely wrong sentence !!

increasing the gas particles will increase the collision between them so !!

your answer is C !!
4 0
3 years ago
Read 2 more answers
Calculate the total pressure in a 10.0 liter flask at 27°C of a sample of gas that contains 6.0 grams of hydrogen, 15.2 grams of
motikmotik

Answer:

The total pressure is 27.8 atm

Explanation:

From the ideal gas equation,

PV = nRT

P (total pressure) = nRT/V

n (total moles of gases) = (6/1 moles of hydrogen) + (15.2/14 moles of nitrogen) + (16.8/4 moles of helium) = 6+1.1+4.2 = 11.3 moles

R = 0.082057L.atm/gmol.K, T = 27°C = 27+273K = 300K, V = 10L

P = 11.3×0.082057×300/10 = 27.8 atm

7 0
3 years ago
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