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3 years ago

calculate the average atomic mass for neon if its abundance in nature is 90.5% neon-20, 0.3% neon-21, and 9.2% neon-22

1 answer:

4 0

The average atomic mass of Neon would simply be the sum of the weighted average of each isotope. That is:

average atomic mass = 0.905 * 20 + 0.003 * 21 + 0.092 * 22

average atomic mass = 20.187 amu

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Solve the following equation (y = 1.2345x – 0.6789) for x, given that y = 0.570

Andrews [41]

x = 1.01

Explanation:

Given equation:

y = 1.2345x – 0.6789

y = 0.570

Problem:

Solving for x

The variables in this equation are y and x

They can take up any value since they are variables.

Since we have been given y = 0.570

y = 1.2345x – 0.6789

To solve for x, we simply substitute for y in the equation;

since y = 0.570

0.57 = 1.2345x – 0.6789

add 0.6789 to both sides;

0.57 + 0.6789 = 1.2345x – 0.6789 + 0.6789

1.2489‬ = 1.2345x

Divide both sides by 1.2345

$\frac{1.2489}{ 1.2345} = \frac{ 1.2345x }{ 1.2345}$

x = 1.01

learn more:

Equations brainly.com/question/9045597

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3 years ago

What is the mass percent of barium in barium cyanide?

GaryK [48]

Answer:

72.521%

Explanation:

7 0

3 years ago

How do the ionic radii vary within a group of non-metals?

stellarik [79]

Answer: Ionic radii is half the distance between two ions.

Explanation: from top to bottom down an element group, ionic radius increases. This is because a new electron shell is added as you move down the periodic table.

Might Be wrong not sure :)

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3 years ago

How many kilograms of solvent would contain 0.43 mol of CaO in a 2.5 molality solution

dalvyx [7]

<h3>Answer:</h3>

0.024 kg CaO

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Aqueous Solutions</u>

Molarity = moles of solute / liters of solution

<u>Atomic Structure</u>

Reading a Periodic Tables
Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.41 mol CaO

2.5 M Solution

<u>Step 2: Identify Conversions</u>

1000 g = 1 kg

Molar Mass of Ca - 40.08 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CaO - 40.08 + 16.00 = 56.08 g/mol

<u>Step 3: Convert</u>

Set up: $\displaystyle 0.43 \ mol \ CaO(\frac{56.08 \ g \ Cao}{1 \ mol \ CaO})(\frac{1 \ kg \ CaO}{1000 \ g \ CaO})$
Multiply: $\displaystyle 0.024114 \ kg \ CaO$