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uysha [10]
4 years ago
5

How to check

d="TexFormula1" title="x - \frac{2}{3 } > \frac{1}{4} " alt="x - \frac{2}{3 } > \frac{1}{4} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
deff fn [24]4 years ago
6 0
Download photomath. step by step equation solver
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Does the point (6, 0) satisfy the equation y = x2?
shtirl [24]

Replace x in the equation with the x value of the point (6) and solve. If it equals the y value (0) it is a solution if it noes not equal (0) it is not a solution.

Y = 6^2 = 36

36 is not 0 so (6,0) is not a solution

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Makovka662 [10]

The slope intercept is equal to the rise/run.


So lets say to get from one point to the other, you go down 2 units and go right 3 units.


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-2/3

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3 years ago
Please help me with this!!!
krok68 [10]

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3 years ago
Dilate ABC below using A as the center and a<br> scale factor of 2. Leave all construction marks?
irina1246 [14]
<h3>Answer: Check out the diagram below.</h3>

Explanation:

Use your straightedge to extend segment AB into ray AB. This means you'll have it start at A and go on forever through B. Repeat these steps to turn segment AC into ray AC.

The two rays join at the vertex angle A. Point A is the center of the universe so to speak because it's the center of dilation. We consider it an invariant point that doesn't move. Everything else will move. In this case, everything will move twice as much compared to as before.

Use your compass to measure the width of AB. We don't need the actual number. We just need the compass to be as wide from A to B. Keep your compass at this width and move the non-pencil part to point B. Then mark a small arc along ray AB. What we've just done is constructed a congruent copy of segment AB. In other words, we've just double AB into AB'. This means the arc marking places point B' as the diagram indicates.

The same set of steps will have us construct point C' as well. AC doubles to AC'

Once we determine the locations of B' and C', we can then form triangle A'B'C' which is an enlarged copy of triangle ABC. Each side of the larger triangle has side lengths twice as long.

Note: Points A and A' occupy the same exact location. As mentioned earlier, point A doesn't move.

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3 years ago
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