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kykrilka [37]
3 years ago
13

Please help me and also show your work 10 points 3(3C2)

Mathematics
1 answer:
Sever21 [200]3 years ago
3 0

Answer:

Step-by-step explanation:

Or if you meant 3(3C^2) then the one under the first one

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How do i find x in questions #20 steps please
Ad libitum [116K]
18- answer is 120
to find this:
first find the remaining angle in ABF
180-(55+40)=180-95=85
F has two angles. if F1 is 85 F2 is 85,too.(coterminal angles)
now you can find the interior angle of CDF
180-(35+85)=180-120=60
the you should find the exterior angle(exterior angle + interior angle =180)
180-60=120
x=120

20
x=48
y=82
ABC is parallel to EF
so to find x: 180-132=48
and for y:
180-((180-130)+48)=180-(50+48)=180-98=82
hope this helps
5 0
3 years ago
Find the minimum and maximum of f(x,y,z)=x2+y2+z2 subject to two constraints, x+2y+z=7 and x−y=6.
sweet-ann [11.9K]
Use the method of Lagrange multipliers. We have Lagrangian

L(x,y,z,\lambda_1,\lambda_2)=x^2+y^2+z^2+\lambda_1(x+2y+z-7)+\lambda_2(x-y-6)

with partial derivatives (set equal to 0) of

L_x=2x+\lambda_1+\lambda_2=0
L_y=2y+2\lambda_1-\lambda_2=0
L_z=2z+\lambda_1=0
L_{\lambda_1}=x+2y+z-7=0
L_{\lambda_2}=x-y-6=0

As x+2y+z=7, and x-y=6, we can obtain

\dfrac12L_x+L_y+\dfrac12L_z=0\implies3\lambda_1-\dfrac12\lambda_2=-7
L_x-L_y=0\implies\lambda_1-2\lambda_2=12
\begin{cases}3\lambda_1-\frac12\lambda_2=-7\\\lambda_1-2\lambda_2=12\end{cases}\implies\lambda_1=-\dfrac{40}{11},\lambda_2=-\dfrac{86}{11}

From this, we find a single critical point:

2x-\dfrac{40}{11}-\dfrac{86}{11}=0\implies x=\dfrac{63}{11}
\dfrac{63}{11}-y=6\implies y=-\dfrac3{11}
\dfrac{63}{11}-\dfrac6{11}+z=7\implies z=\dfrac{20}{11}

At this point, we have a value of

f\left(\dfrac{63}{11},-\dfrac3{11},\dfrac{20}{11}\right)=\dfrac{398}{11}

To determine what kind of extremum occurs at this point, we check the Hessian of f(x,y,z):

\mathbf H(x,y,z)=\begin{bmatrix}f_{xx}&f_{xy}&f_{xz}\\f_{yx}&f_{yy}&f_{yz}\\f_{zx}&f_{zy}&f_{zz}\end{bmatrix}=\begin{bmatrix}2&0&0\\0&2&0\\0&0&2\end{bmatrix}

We observe that \det\mathbf H(x,y,z)=8>0 at any point (x,y,z), and that the eigenvalues of this matrix are all positive (2 with multiplicity 3), so \mathbf H is positive definite. By the second partial derivative test, this means f(x,y,z) attains a minimum at this critical point. Meanwhile, f has no maximum value.
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3 years ago
Y varies directly with x. y=54 when x=9.<br> Determine y when x=3.5
Korolek [52]

Answer:Y=21

Step-by-step explanation:

5 0
4 years ago
What is the solution to the system of equations?
Vesna [10]

Answer:

(4,3)

Step-by-step explanation:

i looked it up on mathaway

3 0
3 years ago
Henrietta has 5 hours to complete her 4 chores. How many hours does she have to do each chore? Choose the correct answer from th
Vlad1618 [11]
The answer is 1 1/4 hours per chore
4 0
4 years ago
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